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Nady [450]
3 years ago
9

Can someone help? Will mark Brainliest

Mathematics
2 answers:
jarptica [38.1K]3 years ago
8 0

Answer: The answer is the 3rd one

Step-by-step explanation:

VARVARA [1.3K]3 years ago
6 0

9514 1404 393

Answer:

  (d)  AE = (32√6)/3

Step-by-step explanation:

The side length ratios in a 30-60-90 triangle are 1 : √3 : 2. In a 45-45-90 triangle, they are 1 : 1 : √2.

So, we have the side length ratios ...

  CE : CD = 2 : √3

  BE : CE = √2 : 1

  AE : BE = 2 : √3

Then the ratio AE : CE is ...

  \dfrac{AE}{CD}=\dfrac{2}{\sqrt{3}}\cdot\dfrac{\sqrt{2}}{1}\cdot\dfrac{2}{\sqrt{3}}=\dfrac{4\sqrt{2}}{3}

Multiplying by the length of CD, we have ...

  AE = (8√3)(4√2)/3

  AE = (32√6)/3 . . . . . matches the last choice

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The radius of a circle is 3.9 in. Find the circumference to the nearest tenth.​
topjm [15]

Answer:

24.5

Step-by-step explanation:

3 0
3 years ago
In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were o
ad-work [718]

The question is incomplete. Here is the complete qeustion.

In a sample of seven cars, each car was tested for nitrogen-oxide emissions (in grams per mile) and the following results were obtained: 0.10 0.13 0.16 0.15 0.14 0.008 0.15

(a) Construct a 99% confidence interval for the mean nitrogen-oxide emissions of all cars.

(b) If the EPA requires that nitrogen-oxide emissions be less than 0.165 g/mi, based on the 99% confidence interval in (a), can we safely conclude that this requirement is being met?

Answer: (a) 0.089 ≤ μ ≤ 0.171

(b) No

Step-by-step explanation:

(a) To determine the confidence interval, first calculate the mean (X) and standard deviation (s) of the sample

X = \frac{0.1+0.13+0.16+0.15+0.14+0.08+0.15}{7}

X = 0.13

s = \sqrt{\frac{(0.1-0.13)^{2} + (0.13 - 0.13)^{2} + ... + (0.15 - 0.13)^{2}}{7-1} }

s = 0.029

The degrees of freedom is

N - 1 = 7 - 1 = 6

And since the confidence is of 99%:

α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005

The t-test statistics for t_{6,0.005} is 3.707

(Value found in the t-distribution table)

Now, calculate Error:

E = t_{6,0.005} . \frac{s}{\sqrt{N} }

E = 3.707. \frac{0.029}{\sqrt{7} }

E = 0.041

The interval will be:  

0.13 - 0.041 ≤ μ ≤ 0.13+0.041

0.089 ≤ μ ≤ 0.171

(b) No, because according to the interval, the nitrode-oxide emissions range from 0.089 to 0.171, which is greater than required by EPA.

7 0
3 years ago
Assume that y varies directly as x.
Anon25 [30]
75/15=5
3*5=15
y would equal 15

Hope this helps :)
4 0
3 years ago
Read 2 more answers
HELP ME PLEASE THANKS
Bezzdna [24]

Answer:

The coefficient is negative because she is traveling downward. -20ft/s represents feet decreasing per second.

She was 350 feet above ground since that is her height at 0 seconds.

It takes her 17.5 seconds to reach the ground.

4 0
3 years ago
What does 2×4+5-3=? Then divide the answer by Five.<br><br>​
Wewaii [24]

Answer:

2

Step-by-step explanation:

2×4+5-3=

8+5-3=10

10/5=2

7 0
3 years ago
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