A product is made up of components A, B, C, D, E, F, G, H, I, and J. Components A, B, C, and F have a 1/10,000 chance of failure
Svetach [21]
Answer:
The overall reliability is 99.7402 %
Step-by-step explanation:
The overall reliability of the product is calculated as the product of the working probability of the components.
For components A,B,C and F we have :

⇒

For components D,E,G and H we have :

⇒

Finally, for components I and J :

⇒

Now we multiply all the working probabilities. We mustn't forget that we have got ten components in this case :
Components A,B,C and F with a working probability of 0.9999
Components D,E,G and H with a working probability of 0.9997
Components I and J with a working probability of 0.9995
Overall reliability = 
0.997402 = 99.7402 %
First option is correct.
Since we have given that
JKL is a right triangle.
Length of JK = 12
Length of KL = 5
By Pythagoras theorem, we get that

So, cos (L) would be
cos(L)=base/hypotenuse
cos(L)=5/13
Hence, First option is correct.
learn more about Pythagoras theorem and cosine ratios here:
brainly.com/question/9027282
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Answer:
Step-by-step explanation:
x-4=0
x=4
p(x)=cx^3-15x-68=0
p(x)=c(4)^3-15(4)-68=0
p(x)=64c-60+68=0
p(x)=64c+8=0
p(x)=64c=-8
p(x)=c=-8/64
p(x)=c=-1/8
<u>Part 1)</u> A 20° sector in a circle has an area of 21.5π yd².
What is the area of the circle?
we know that
the area of a circle represent a sector of
degrees
so by proportion
therefore
<u>the answer part 1) is</u>
The area of the circle is 
<u>Part 2)</u> What is the area of a sector with a central angle of 3π/5 radians and a diameter of 21.2 cm?
we know that
the area of the circle is equal to

where
r is the radius of the circle
in this problem we have

<u>Find the area of the circle</u>



<u>Find the area of the sector</u>
we know that the area of the circle represent a sector of
radians
by proportion
therefore
<u>the answer part 2) is</u>
the area of the sector is

.07Step-by-step explanation:
2xtimes 10 times 2