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3 years ago

Solve the equation. 6(x−2)=−18 x=

Mathematics

2 answers:

iVinArrow [24]3 years ago

8 0

Answer: x= -1

Step-by-step explanation:

divide both sides by 6

add 2 to each side

quester [9]3 years ago

3 0

Answer:

x=-1

Step-by-step explanation:

6(x-2)=-18

6x-12=-18

6x=-6

x=-1

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A product is made up of components A, B, C, D, E, F, G, H, I, and J. Components A, B, C, and F have a 1/10,000 chance of failure

Svetach [21]

Answer:

The overall reliability is 99.7402 %

Step-by-step explanation:

The overall reliability of the product is calculated as the product of the working probability of the components.

For components A,B,C and F we have :

$P(failure)=\frac{1}{10000}$

⇒

$P(Work)=1-\frac{1}{10000}=\frac{9999}{10000}=0.9999$

For components D,E,G and H we have :

$P(failure)=\frac{3}{10000}$

⇒

$P(Work)=1-\frac{3}{10000}=\frac{9997}{10000}=0.9997$

Finally, for components I and J :

$P(failure)=\frac{5}{10000}$

⇒

$P(Work)=1-\frac{5}{10000}=\frac{9995}{10000}=0.9995$

Now we multiply all the working probabilities. We mustn't forget that we have got ten components in this case :

Components A,B,C and F with a working probability of 0.9999

Components D,E,G and H with a working probability of 0.9997

Components I and J with a working probability of 0.9995

Overall reliability = $(0.9999)^{4}(0.9997)^{4}(0.9995)^{2}=0.997402$

0.997402 = 99.7402 %

6 0

3 years ago

Given right triangle JKL, what is the value of cos(L)?

Daniel [21]

First option is correct.

Since we have given that

JKL is a right triangle.

Length of JK = 12

Length of KL = 5

By Pythagoras theorem, we get that

$JL^{2}=JK^{2}+ KL^{2}\\JL^{2}=12^{2}+ 5^{2} \\JL^{2}=144+25= 169\\JL=13$

So, cos (L) would be

cos(L)=base/hypotenuse

cos(L)=5/13

Hence, First option is correct.

learn more about Pythagoras theorem and cosine ratios here:

brainly.com/question/9027282

#SPJ1

6 0

1 year ago

Find the value of c so that the polynomial p(×) is divisible by (x-4). p(×)=cx^3-15x-68

Dvinal [7]

Answer:

Step-by-step explanation:

x-4=0

x=4

p(x)=cx^3-15x-68=0

p(x)=c(4)^3-15(4)-68=0

p(x)=64c-60+68=0

p(x)=64c+8=0

p(x)=64c=-8

p(x)=c=-8/64

p(x)=c=-1/8

7 0

2 years ago

1.) A 20° sector in a circle has an area of 21.5π yd².

a_sh-v [17]

Part 1) A 20° sector in a circle has an area of 21.5π yd².

What is the area of the circle?

we know that

the area of a circle represent a sector of $360$ degrees

so by proportion

$\frac{21.5\pi }{20} =\frac{x}{360} \\ \\ x*20=360*21.5\pi \\ \\x=(360*21.5*3.14)/20\\ \\x= 1,215.18\ yd^{2}$

therefore

the answer part 1) is

The area of the circle is $1,215.18\ yd^{2}$

Part 2) What is the area of a sector with a central angle of 3π/5 radians and a diameter of 21.2 cm?

we know that

the area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

in this problem we have

$Diameter=21.2\ cm\\ r=Diameter/2\\r=21.2/2\\r= 10.6\ cm$

Find the area of the circle

$A=\pi r^{2}$

$A=\pi*10.6^{2}$

$A=352.8104\ cm^{2}$

Find the area of the sector

we know that the area of the circle represent a sector of $2\pi$ radians

by proportion

$\frac{352.8104}{2\pi }=\frac{x}{(3\pi/5)} \\\\x*2\pi=(3\pi*352.8104)/5\\ \\x= 105.84\ cm^{2}$

therefore

the answer part 2) is

the area of the sector is

$105.84\ cm^{2}$

7 0

3 years ago

The probability that Leon makes a three-point shot in basketball is 15%. For practice, Leon will regularly

mr_godi [17]

.07Step-by-step explanation:

2xtimes 10 times 2

3 0

3 years ago

Read 2 more answers