Answer:
x= 37/36
Step-by-step explanation:
−12(3x−4)=11
Step 1: Simplify both sides of the equation.
−12(3x−4)=11
(−12)(3x)+(−12)(−4)=11(Distribute)
−36x+48=11
Step 2: Subtract 48 from both sides.
−36x+48−48=11−48
−36x=−37
Step 3: Divide both sides by -36.
−36x
−36
=
−37
−36
x=
37
36
Answer:
x=
37
36
A) x² + y² = 327
B) x * y = 101
Solving equation B for y²
B) y² = 10,201 / x²
Substituting this into equation A)
x² + 10,201 / x² = 327
x^4 + 10,201 = 327x²
x^4 -327x² + 10,201 = 0
Using the quartic equation calculator: http://www.1728.org/quartic.htm
x1 = 17.090169943749476
x2 = 5.909830056250525
x1 * x2 = 101
x1 + x2 = 23
You did not include the questions, but I will give you two questions related with this same statement, and so you will learn how to work with it.
Also, you made a little (but important) typo.
The right equation for the annual income is: I = - 425x^2 + 45500 - 650000
1) Determine <span>the youngest age for which the average income of
a lawyer is $450,000
=> I = 450,000 = - 425x^2 + 45,500x - 650,000
=> 425x^2 - 45,000x + 650,000 + 450,000 = 0
=> 425x^2 - 45,000x + 1,100,000 = 0
You can use the quatratic equation to solve that equation:
x = [ 45,000 +/- √ { (45,000)^2 - 4(425)(1,100,000)} ] / (2*425)
x = 38.29 and x = 67.59
So, the youngest age is 38.29 years
2) Other question is what is the maximum average annual income a layer</span> can earn.
That means you have to find the maximum for the function - 425x^2 + 45500x - 650000
As you are in college you can use derivatives to find maxima or minima.
+> - 425*2 x + 45500 = 0
=> x = 45500 / 900 = 50.55
=> I = - 425 (50.55)^2 + 45500(50.55) - 650000 = 564,021. <--- maximum average annual income
Answer:
goes with 
goes with 
goes with 
Step-by-step explanation:
by the addition identity for cosine.
We are given:
which if we look at the unit circle we should see
.
We are also given:
which if we look the unit circle we should see
.
Apply both of these given to:
by the addition identity for cosine.
Apply both of the givens to:
by addition identity for sine.
Now I'm going to apply what 2 things we got previously to:
by quotient identity for tangent
Multiply top and bottom by bottom's conjugate.
When you multiply conjugates you just have to multiply first and last.
That is if you have something like (a-b)(a+b) then this is equal to a^2-b^2.
There is a perfect square in 12, 4.
Divide top and bottom by 4 to reduce fraction:
Distribute:
