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2 years ago

Select the correct answer. What is the value of X in the triangle?

Mathematics

2 answers:

arlik [135]2 years ago

5 0

Answer:

Step-by-step explanation:

The sum of all the angles of a triangle always equals 180 degrees. Write down the difference you found when subtracting the sum of the two angles from 180 degrees. This is the value of X.

mash [69]2 years ago

4 0

^^ she is right so yeah lol

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3x+122=22x-11<br>i need help!

nasty-shy [4]

3x + 122 = 22x - 11

+11 + 11

3x + 133 = 22x

-3x -3x

133 = 19x

x = 7

5 0

2 years ago

Read 2 more answers

A given line has the equation 2x + 12y = −1. What is the equation, in slope-intercept form, of the line that is perpendicular to

VikaD [51]

Answer:

y = 6x + 9

Step-by-step explanation:

The equation of a line in slope- interceot form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 2x + 12y = - 1 into this form

Subtract 2x from both sides

12y = - 2x - 1 ( divide all terms by 12 )

y = - $\frac{1}{6}$ x - $\frac{1}{12}$ ← in slope- intercept form

with slope m = - $\frac{1}{6}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-\frac{1}{6} }$ = 6

Note the line passes through (0, 9) on the y- axis ⇒ c = 9

y = 6x + 9 ← equation of perpendicular line

3 0

2 years ago

Read 2 more answers

Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop

xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

f(x)=log (3 x) +5 x²

$f'(x)=\frac{1}{3x}+10 x$

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

$x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248$

$x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012$

$x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057$

$x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052$

So, root of the equation =0.205 (Approx)

Approximate relative error

$=\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41$

Approximate relative error in terms of Percentage

=0.41 × 100

= 41 %

7 0

2 years ago

Y = – 1.3(x + 3)2 – 9

Naddika [18.5K]

Given equation, y = – 1.3(x + 3)2 – 9 is in slope intercept form.

Step-by-step explanation:

Slope intercept form standard formula:

y = mx + c

where,

y= y intercept

x= x intercept

m = slope

c = constant

We are given:

y = - 1.3(x + 3)2 - 9

y = - 2.6x + 7.8 - 9

y = -2.6x -1.2

So,

Slope = m = -2.6

constant = 1.2

6 0

3 years ago

Find the x-intercept and y-intercept of the liné.<br> - 6x + 5y = 21

Hunter-Best [27]

Answer:

x=-3.5 or -7/2 (same thing)

y=21/5

Step-by-step explanation:

x intercept is when y=0

y intercept is when x=0

x intercept is

-6x=21

x=21/-6

x=-3.5

y intercept is

5y=21

y=21/5

7 0

2 years ago