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abruzzese [7]
4 years ago
11

BRAINLIEST ANSWER GIVEN Solve inequality and write interval notation.

exFormula1" title="5x+4\leq x-8" alt="5x+4\leq x-8" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Anuta_ua [19.1K]4 years ago
7 0

Answer:

x\leq -3

Step-by-step explanation:

I can't write interval notation on Brainly but I can solve the inequality.

5x+4\leq x-8

<em>Subtract </em>x<em> from both sides</em>

4x+4\leq -8

<em>Subtract 4 from both sides</em>

4x\leq -12

<em>Divide both sides by 4</em>

x\leq -3

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slavikrds [6]

Answer:

-3: Integer

21: Whole #

0.9: Rational

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3.2: Rational

53: Whole #

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8: Whole #

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3/4: Rational

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Step-by-step explanation:

See above.

If you can please make my answer the brainliest that would be much appreciated. Thanks and Good Luck! :D

4 0
3 years ago
Suppose that the functions s and t are defined for all real numbers x as follows.
jeka94

Answer:

(s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39

Step-by-step explanation:

Given functions are:

s(x)= x+6\\t(x)= 4x^2

We have to find:

(s.t)(x) => this means we have to multiply the two functions to get the result.

So,

(s.t)(x) = s(x)*t(x)\\= (x+6)(4x^2)\\=4x^2.x+4x^2.6\\=4x^3+24x^2

Also we have to find

(s-t)(x) => we have to subtract function t from function s

(s-t)(x) = s(x) - t(x)\\= (x+6) - (4x^2)\\=x+6-4x^2

Also we have to find,

(s+t)(-3) => first we have to find sum of both functions and then put -3 in place of x

(s+t)(x) = s(x)+t(x)\\= x+6+4x^2

Putting x = -3

= -3+6+4(-3)^2\\=-3+6+4(9)\\=3+36\\=39

Hence,

(s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39

8 0
3 years ago
131.12 divided by 44
Alona [7]

Answer:2.98

Step-by-step explanation:

4 0
3 years ago
-5 5/6-(-2 1/3)+5 1/6
Umnica [9.8K]

Answer: 1.66666666667

5 0
2 years ago
What is the answer to: 3(-3-3x) 4=-5?
Anna35 [415]
Your answer will be x=-2
6 0
4 years ago
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