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Fudgin [204]
3 years ago
7

CloudPort

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
3 0

Answer:

(1) P(Heart\ and\ Club) = 0.0494

(2) S = \{B,B,B,B,R,R,R,R,R,Y,Y,Y,Y,Y,Y,Y,Y\}

Step-by-step explanation:

Question 1:

Given

Hearts = 8

Diamond = 3

Club=2

Spade = 5

Total = 18

Required

Probability of 1 heart and 1 club

This probability is calculated as:

P(Heart\ and\ Club) = P(Heart) * P(Club)

P(Heart\ and\ Club) = \frac{n(Heart)}{Total} * \frac{n(Club)}{Total}

P(Heart\ and\ Club) = \frac{8}{18} * \frac{2}{18}

P(Heart\ and\ Club) = \frac{8*2}{18*18}

P(Heart\ and\ Club) = \frac{16}{324}

P(Heart\ and\ Club) = 0.0494 -- approximated

Question 2:

Given

Blue = 4

Red= 5

Yellow = 8

Required

Determine the sample space

Represent the blue balls with B, the red with R and the yellow with Y.

The sample space (S) is:

S = \{B,B,B,B,R,R,R,R,R,Y,Y,Y,Y,Y,Y,Y,Y\}

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