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3 years ago

What is the measure of Z ABC ? B 60° 60° c

Mathematics

1 answer:

prisoha [69]3 years ago

6 0

Answer:

60°

Step-by-step explanation:

If it a equilateral triangle

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We looking for distance

drek231 [11]

Answer:

240 m

Step-by-step explanation:

Figure is attached.

The distance the particle travels is the area under the v-t graph over the time interval from 0 min to 4 min. The reason you can't just multiply velocity by time is that the velocity is changing at a constant rate over the given time interval (the line is going upward--the particls is speeding up).

What's the area under the graph?

The red outline forms a trapezoid. The area of a trapezoid is $A=\frac{1}{2}h(b_1+b_2)$ where the <em>b</em>'s are the lengths of the two parallel base and <em>h</em> is the height (the distance between the bases).

Reading the graph carefully (notice the scales!)...

$A=\frac{1}{2}(4)(30+90)=(2)(120)=240 \text{m}$

8 0

3 years ago

I really need help I would appreciate it if someone could help me

sleet_krkn [62]

Answer:

a) The vertex of the graph is $(h,k) = (0, 31)$ , b) $a = -16$ , c) The equation of the parabola is $f(t) = -16\cdot t^{2}+31$ .

Step-by-step explanation:

a) The tennis ball experiments a free fall, that is, an uniform accelerated motion due to gravity and in which effects from Earth's rotation and air viscocity are negligible. The height of the ball in time is represented by a second order polynomial. Hence, the vertex of the parabola is the initial point highlighted in graph.

The vertex of the graph is $(h,k) = (0, 31)$ .

b) If we know that $(h,k) = (0, 31)$ , $f(t) = a\cdot (t-h)^{2} + k$ and $(t,f(t)) = (1,15)$ , then the value of $a$ is:

$f(t) = a\cdot (t-h)^{2} + k$

$15 = a\cdot (1-0)^{2}+31$

$15 = a\cdot 1 + 31$

$a = 15-31$

$a = -16$

c) The equation of the parabola is $f(t) = -16\cdot t^{2}+31$ .

4 0

3 years ago

Can y'all help me with number 6.

Juliette [100K]

SOH CAH TOA -> $\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad 
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}

\\ \quad \\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}$

so.. which of those fellows do we use?
well, the triangle gives us

the angle, 15 degrees, for elevation angle
the adjacent side, 50m
and we want the opposite side, the slide

so...who has only, the angle, opposite, and adjacent sides?
well, low and behold, is Ms tangent
thus
$\bf tan(\theta)=\cfrac{opposite}{adjacent}\qquad 
\begin{cases}
\theta\to 15^o\\
adjacent=50\\
opposite=x-15
\end{cases}
\\ \quad \\
tan(15^o)=\cfrac{x-15}{50}\implies 50tan(15^o)=x-15\\\\ 50\cdot tan(15^o)+15=x$

notice, "x" in the picture, is the distance from the ground up to the top of the waterslide, using that triangle, what we're getting is just the distance, from the shorter slide, to the taller one, or x - 15
thus, the opposite side is x -15

6 0

3 years ago

I need help with this lol

emmainna [20.7K]

Answer:

32 i think

Step-by-step explanation:

8 0

3 years ago

A/b(2x-12)=c/d solve for x

GenaCL600 [577]

Let's solve for x.

Layout equation:

a/b

(2x−12)=c/d

Step 1: Multiply both sides by b.

2ax−12a=bc/d

Step 2: Multiply both sides by d.

2adx−12ad=bc

Step 3: Add 12ad to both sides.

2adx−12ad+12ad=bc+12ad

2adx=12ad+bc

Step 4: Divide both sides by 2ad.

2adx/2ad=12ad+bc/2ad

So the answer is x=12ad+bc/2ad.

8 0

4 years ago

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What is the measure of Z ABC ? B 60° 60° c​

What is the measure of Z ABC ? B 60° 60° c