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Crank
3 years ago
15

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA 40 POINTS* DONT SKIP :(( .!

Mathematics
1 answer:
Nat2105 [25]3 years ago
4 0
Relative dating is the answer
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Dave wants to buy a new collar for each of his 4 cats. The collars come in a choice of 8 different colors. How many selections o
irga5000 [103]

Answer:

4096.

Step-by-step explanation:

We have been given that Dave wants to buy a new collar for each of his 4 cats. The collars come in a choice of 8 different colors. We are asked to find the number of selections of collars for the 4 cats if repetitions of colors are allowed.

Since repetitions are allowed, so collars for each cat be chosen in 8 different ways.

Total number of selections would be 8\times 8\times 8\times 8=4096

Therefore, there are 4096 possible selections of collars.

4 0
3 years ago
Robert gives $50 each month to charity his monthly salary is $1,575 does Robert give more or less than 2% of his monthly salary
Thepotemich [5.8K]
No 2% of 1,575 is only 31.5
5 0
3 years ago
The following question has two parts. First, answer part A. Then, answer part B.
Pie

Answer:

When you're talking factors, you're talking about some sort of integer; that's because “factors” depends on the concept of divisibility, which are virtually exclusive to integers. When you're talking “greater than”, you're excluding complex numbers (where the concept of ordering doesn't exist) and you're probably assuming positive integers. If you are, then no; no positive integer has factors that are larger than it.

If you go beyond positive numbers, that changes. 0 is an integer, and has every integer, except itself, as factors; since its positive factors are greater than zero, there are factors of zero that are greater than zero. If you extend to include negative numbers, you always have both positive and negative factors; and since all positive integers are greater than all negative integers, all negative integers have factors that are greater than them.

Beyond zero, though, no integer has factors whose magnitudes are greater than its own. And that's a principle that can be extended even to the complex integers

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please Help!
natita [175]

\bf (7x-6)\times (3x^2-4x+5)\implies \begin{array}{cllll} 3x^2-4x+5\\ \times 7x\\\cline{1-1} 21x^3-28x^2+35x \end{array}~~ +~~ \begin{array}{cllll} 3x^2-4x+5\\ \times -6\\\cline{1-1} -18x^2+24x-30 \end{array} \\\\\\ 21x^3-28x^2+35x~~+~~(-18x^2+24x-30)\implies \boxed{21x^3-46x^2+59x-30}

3 0
3 years ago
1. f(x) = 3x + 5<br> X<br> f(x)
strojnjashka [21]

Answer:37x

Step-by-step explanation:

5 0
3 years ago
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