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Nata [24]
3 years ago
5

If a father has type A blood and the mother has Type AB blood, they would NOT have a child with which of the following blood typ

es?
AB

A

B

O
Biology
1 answer:
horsena [70]3 years ago
4 0

Answer:

If a father has type A blood and the mother has type AB blood, they cannot have a child with blood type O, although depending on the father's genotype, they may not have children with a B blood type either.

Explanation:

Blood type is determined by the presence or absence of surface antigens A and B, which is genetically determined and establishes the pattern of inheritance.

<u>Alleles that define the presence of antigens A and B are co-dominant, while the absence of antigens - as in blood type O - is a recessive trait</u>.

  • <em>Type A </em><em>contains antigen A and its genotype can be A|A or A|O. </em>
  • <em>Type B</em><em> contains the B antigen, whose genotype can be B|B or B|O. </em>
  • <em>Blood type AB</em><em> contains both antigens and a single genotypic expression A|B </em>
  • <em>Type O blood </em><em>lacks surface antigens, with genotype O|O.</em>

The father with blood type A can have two genotypes, A|A or A|O, which raises 2 possible scenarios:

1. <u>Father A|O with mother A|B </u>

Alleles       A         O

A              A|A      A|O

B              A|B      B|O

In this case there is no chance of having a child with blood type O, 50% chance of having children with blood type A, 25% B and 25% AB.

2. <u>Father A|A with mother A|B </u>

Alleles        A        A

A               A|A     A|A

B               A|B     A|B

50% chance of having a child with blood type A and 50% with blood type AB. In this case there is no chance of having children with blood type O or B.

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Answer:

Yes possible

Explanation:

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Answer:

For sample A, A=17.7 %, T=17.7 %, G=32.30%, C=32.30%

For sample B, A= 28.9%, T=28.9%, G= 21.10%, C= 21.10%

Explanation:

The composition of nitrogenous bases in DNA is calculated using the suggestions proposed by the results of the experiment performed by Erwin Chargaff.

He found that in a DNA sample the composition of purine to pyrimidine is 1:1. This indicates that the amount of purine equals pyrimidine. This can be presented as purines + pyrimidines= 100. Also, adenine binds thymine and cytosine binds guanine.

In the given question,  

<u>For sample A </u>

A= 17.7 %, Therefore, thymine will be = 17.7 %,

A+T= 35.40%

Now, G+C=100- 35.40%

G+C= 64.60%

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content of C= 32.30%

<u>For sample B </u>

T=28.9%, A will be= 28.9%

A+T= 57.80%

G+C=100-57.80%

G+C= 42.20%

Thus content of G will be= 42.20/2=21.10

content of C= 21.10%

Thus,  

For sample A, A=17.7 %, T=17.7 %, G=32.30%, C=32.30%

For sample B, A= 28.9%, T=28.9%, G= 21.10%, C= 21.10%

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