Answer:
I think right answer is integers
Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
<span><span><span><span>3/4</span>x</span>+11 </span>< <span><span>0.3x</span>+<span>3/4
</span></span></span>First turn 3/4 from both sides to decimals to get..
.75x+11 < 0.3x+.75
And then subtract 0.3x from both sides to get
.45x+11 < .75
And then subtract 11 from both sides to get
.45x < -10.25
And then divide both sides by .45x to get
x < -22.77777778
bro
Step-by-step explanation:
