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3 years ago

What is equivalent to -2(x5)

Mathematics

1 answer:

anzhelika [568]3 years ago

3 0

-10x is the final answer
Hope this helps

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What is the length of an arc defined by a 60 degree central angle in a circle with a radius of 5 in.?

Natali [406]

Answer:

5.24 in

Step-by-step explanation:

The arc length is calculated as

arc = circumference × fraction of circle

= 2πr × $\frac{60}{360}$

= 2π × 5 × $\frac{1}{6}$

= $\frac{10\pi }{6}$ ≈ 5.24 in (2 dec. places )

3 0

3 years ago

What is cross products

Reil [10]

Is a binary operation on two vectors in three-dimensional space, and is denoted by the symbol. Given two linearly independent vectors a and b, the cross product, a × b, is a vector that is perpendicular to both a and b, and thus normal to the plane containing them.

4 0

3 years ago

A small metal bar, whose initial temperature was 10° C, is dropped into a large container of boiling water. How long will it tak

IgorC [24]

Answer

According to newton law of cooling

$\dfrac{d T}{dt} = k (T - T_a)$

and

$T = Ce^{kt} + T_a$

now At Ta = 100

T₀ = 10 °C

T₁ = 12° C

$T(0) = Ce^{0} + T_a$

10 = C + 100

C = -90

now,

$12 = -90e^k + 100$

$e^k = \dfrac{88}{90}$

$k = ln{\dfrac{88}{90}}$

at time equal to t

T(t) = 70

$T(t) = -90 (\dfrac{88}{90})^t + 100$

$70 = -90(\dfrac{88}{90})^t + 100$

$(\dfrac{88}{90})^t = \dfrac{1}{3}$

$t\times ln(\dfrac{88}{90}) = ln(\dfrac{1}{3})$

t = 48.88 s

hence, after 48.88 s the temperature of the body will be 70°C

b) time taken to reach 98°C

$T(t) = -90 (\dfrac{88}{90})^t + 100$

$98 = -90(\dfrac{88}{90})^t + 100$

$(\dfrac{88}{90})^t = \dfrac{1}{45}$

$t\times ln(\dfrac{88}{90}) = ln(\dfrac{1}{45})$

t = 390 s

hence, after 390 s the temperature of the body will be 98°C

5 0

3 years ago

Please answer this question needed ASAP !!

butalik [34]

Angle F should be 46 degrees

6 0

3 years ago

You are on the south side of a river and you need to cross the river in order to get to a campsite. Not

Doss [256]

Answer:

Width of river = 0.25 mile

As length of river is not given , but it is given that campsite is located 1 mile east upstream, So length of river = 1 mile

Speed of mine in river while going upstream = 3 miles per hour

Speed of current as going Upstream = 1 miles per hour

Now Reduced speed of mine = Speed of mine in river while going upstream - Speed of current as going Upstream

= 3 - 1

= 2 miles per hour

1. There are two ways to reach campsite

(a) either walk 1 mile from starting point in east direction and then swim 0.25 mile in North direction to reach campsite.

(b) From the starting point Considering a right triangle having, base=1 mile and altitude = 0.25 mile, then finding the length of hypotenuse using formula = $\sqrt{(altitude)^2 + (Base)^2$

= $\sqrt{.25^2+1^2}$

=√1.0625

=1.03078(approx)

⇒ you must walk a distance of 1 mile in the east direction and then swim 0.25 mile north direction to reach directly at campsite.[shown in the diagram]

7 0

3 years ago