Answer:
Response:<em> B[g]= A[f]+ A[f + 1]; </em>
<em>Explanation: </em>
• The very first command "LSL, X9, X0, #3" was to multiply the factor "f" by "8" use the shift function, this really is essential to get 8-byte words from the arrays.
• The next command was to enter the array element "A" with index "f," the index of A[f] would be in' X9' from the first instruction implementation.
• The third and fourth instructions are the same as first and second statements however the array will be "B" and the index will be "g"
• The fifth statement "LDUR X0,[ X9, #0]" will assign the array value in "A[f]" to the variable "f" located in X0.
• The sixth command "ADDI X11, X9, #8" should lead in the next array value being stored after the "X11" address "A[f]," which is the value of the item A[f+1].
• The next command "LDUR X9,[ X11,#0]" would be to load the command to "X9."
• The next "ADD X9, X9, X0" instruction results in the addition of X0 with X9 contents, i.e. A[f] and A[f+1] array contents, resulting in X9 register.
• During the last request, the value stored in X9 is stored in X10, assigned to the address of B[ g] • Therefore, the overall operation performed by the instructions given is: B[g]= A[f]+ A[f + 1]
Therefore, the related C statement is B[g]= A[f]+ A[f + 1].
