Suppose that 11 inches of wire costs 33 cents. At the same rate, how many inches of wire can be bought for 18 cents?

Mathematics

2 answers:

VikaD [51]2 years ago

6 0

Answer:6 inches

Step-by-step explanation:

11inch=33 cents

1 cent can buy 11/33= 1/3 inches

18 cents can buy 18 * 1/3 = 6 inches

neonofarm [45]2 years ago

6 0

Answer:

6in. = 18 cents

Step-by-step explanation:

1. Find out how many inches it costs for one inch ( 33/11 = 3)

2. divide 18 by 3 and get 6.

You might be interested in

NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t2+121t

Alenkasestr [34]

NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by

$h(t)=-4.9t^2+121t+283$

The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:

$h(t)=0\implies-4.9t^2+121t+283=0$

Using the quadratic formula, the solution for our problem is

$\begin{gathered} t=\frac{-(121)\pm\sqrt{(121)^2-4(-4.9)(283)}}{2(-4.9)} \\ =\frac{121\pm142.083778...}{9.8} \\ =\frac{121+142.083778...}{9.8} \\ =26.8452834694... \end{gathered}$

The rocket splashes after 26.845 seconds.

The maximum of this function happens at the root of the derivative. Differentiating our function, we have