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3 years ago

Nicole has x dimes and y nickels. She has at least 15 coins worth a maximum of $1

Mathematics

1 answer:

Sonbull [250]3 years ago

7 0

Answer:

Step-by-step explanation:

$X + Y \geq 15\\\\10X + 5Y \leq 100$

we want to put it into terms of Y

$y \geq 15 - x\\and\\5y \leq 100 - 10x\\y \leq 20 - 2x$

the graph is in the attached image. Any point in the shaded overlap region where x is greater than or equal to 0 (assuming you cannot have negative coins) works, e.g. (2, 14)

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What is angle M? Just checking work

Artist 52 [7]

Sum of interior angles = 180
180 - 60 = 120

120/4 = 30
m<L = m<A = 60
m<M = 30
m<C = m<N = 3(m<M) = 3(30) = 90

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3 years ago

140% out of what gives 56

Verizon [17]

140 / 100 * X = 56

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3 years ago

Read 2 more answers

Which is the solution to the following system?<br><br> y=3x+1 <br> 6x-2y=4

zalisa [80]

Answer:

x=-7/3 and y=-6

Step-by-step explanation:

6x-3(3x+1)=4

6x-9x-3=4

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x=-7/3

y=3(-7/3)+1

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8 0

3 years ago

AYUDA CON ESTO!!! ALGUIEN PORFAVOR

Gre4nikov [31]

Answer:

Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

$Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds$

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

$\frac{200}{60} = \frac{10}{3} \approx 3.33$ loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

$\frac{200}{65} = \frac{40}{13} \approx 3.08$ loops per minute

then the period is:

$\frac{13}{40} =0.325\,\,\,minutes$

Therefore runner B has the smaller period

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3 years ago

ABCD is a rectangle. AD = 15, AC = 25, and DC = 20. Find BD.

agasfer [191]

Answer:

Step-by-step explanation:

it is the same length as DC just going diagonal.

(i am not good at explaining in case you could not tell)

6 0

3 years ago