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DIA [1.3K]
3 years ago
10

How many significant figures is in 1234

Chemistry
1 answer:
DENIUS [597]3 years ago
8 0

Answer:

4 significant figures.

Explanation:

The given measurement have four significant figures 1234.

All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.

Leading zeros are not consider as a significant figures. e.g. 0.03 in this number only one significant figure present which is 3.

Zero between the non zero digits are consider significant like 104 consist of three significant figures.

The zeros at the right side e.g 2400 are also significant. There are four significant figures are present.

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During a lab, you heat 1.62 g of a CoCl2 hydrate over a Bunsen burner. After heating, the final mass of the dehydrated compound
sashaice [31]
Answer is: formula of hydrate is CoCl₂· 6H₂O -c<span>obalt(II) chloride hexahydrate
</span>m(CoCl₂· xH₂O) = 1,62 g.
m(CoCl₂) = 0,88 g.
n(CoCl₂) = m(CoCl₂) ÷ M(CoCl₂)
n(CoCl₂) = 0,88 g ÷ 130 g/mol
n(CoCl₂) = 0,0068 mol.
m(H₂O) = 1,62 g - 0,88 g.
m(H₂O) = 0,74 g.
n(H₂O) = m(H₂O) ÷ m(H₂O) 
n(H₂O) = 0,74 g ÷ 18 g/mol
n(H₂O) = 0,041 mol.
n(CoCl₂) : n(H₂O) = 0,0068 mol : 0,041 mol.
n(CoCl₂) : n(H₂O) = 1 : 6.
8 0
4 years ago
How do you find percent composition?
Tatiana [17]

Answer:

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Explanation:

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4 0
3 years ago
hola genteee ayuda me pueden decir 5 propiedades físicas y 5 propiedades químicas del ácido sulfúrico porfa es urgente !
Alexus [3.1K]

Answer:

La respuesta está en la explicación.

Explanation:

Las propiedades físicas son las visibles y medibles que no afectan químicamente la sustancia en cuestión. Las propiedades químicas hacen alusión a la reactividad de la sustancia:

Propiedades físicas ácido sulfúrico:

Líquido a temperatura ambiente.

Densidad: 1.83g/mL

Punto de fusión: 10°C

Punto de ebullición: 337°C

Índice de refracción: 1.397

Propiedades Químicas:

Ácido Fuerte.

Oxidante Fuerte.

Miscible con el agua reaccionando exotérmicamente.

A temperaturas > 30°C produce vapores azufrados.

Estable en concentraciones menores al 98%

8 0
4 years ago
When an excited electron in a hydrogen atom falls from ????=5 to ????=2, a photon of blue light is emitted. If an excited electr
poizon [28]

Answer:

n = 3

Explanation:

Given the formula for the transition energy of an atom with 1 electron:

E=-13.6*Z^{2}*(\frac{1}{n_{f}^{2}}-\frac{1}{n_{i}^{2}} ) eV

For the H transition n=5 to n=2:

E=-13.6*(\frac{1}{4}-\frac{1}{25} ) eV=-2.856 eV

Then we solve for nf with Z=2 (Helium)

n_{f}=\sqrt{\frac{n_{i}^{2}*Z^{2}*13.6 eV }{2.856eV*n_{i}^{2}+13.6eV*Z^{2}} }

n_{f}=\sqrt{\frac{4^{2}*2^{2}*13.6 eV }{2.856eV*4^{2}+13.6eV*2^{2}} }=3

Is near 3, actually the energy of the transitions are:

H (5⇒2) = -2.85 eV = 434 nm (Dark blue)

He (4⇒3) = -2.64 eV = 469 nm (Light blue)

I thought it was cool to see the actual colors. Included them.

4 0
3 years ago
How many chlorine particles are in 4.5 moles in sig figs
Mariana [72]

Answer:

2.71×10²⁴ particles

Explanation:

Applying Avogadro's constant

Avogadro's constant states that, The number of specified particles contained in a mole of a substance is equal to 6.02×10²³.

From the question,

If one mole of chlorine contains a particle of  6.02×10²³,

Therefore,

4.5 moles of chlorine will contain a particle of (4.5× 6.02×10²³)

⇒ 27.09×10²³

Hence the number of particle contained in 4.5 moles of chlorine ≈ 2.71×10²⁴ particles

6 0
3 years ago
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