Answer:
Explanation:
a. Oxidation : 2O + 4e^- ------> 2O^2-
b. Reduction: 2Sr - 4e- -------> Sr^2+
c. Balanced redox reaction
2Sr + O2 ------------> 2Sr O
Oxidation and reduction can be defined by various means, addition of oxygen, removal of hydrogen, removal of electrons. For this reaction, this definition is used, oxidation is the loss of electrons while reduction is the gaining of electrons.
In (a) oxidation half reaction, the valency of oxygen is zero and then moves into lossing two electrons resulting into -2 valency.
In (b) reduction half reaction, the valency of Sr is zero and gains electrons resulting into valency of 2.
In the overall redox reaction, Sr and O2 with valency of 0 each reacts together and form SrO with valency of 2 and -2 respectively, which gives 0 and then balances the equation.
Answer:
K is a group 1 element while Ne is a group 0 element
K is a good reducing agent while Ne is inert
K is metal while Ne is a gas
K has one valence electron while Ne has no valence electron
Explanation:
No! Acetone is a compound :)
Answer:
V2= 531.4 ml
Explanation:
T1= 273+45 °C= 318 Kelvin
T2= 273+65 °C= 338 Kelvin
V1= 500ml *( 0.001L/1ml)= 0.5 Liters
V2= 
= 
= 0.5314465409 Liters* (1 ml/0.001 L)= 531.4 ml
Explanation:
For all of the questions, do the following calculation
As an example, I'll do question 1
