Answer:
C. $97
Step-by-step explanation:
The average of his wage for all 15 days is the sum of all wages for the 15 days divided by 15.
average wage for 15 days = (sum of wages for the 15 days)/15
The amount of wages during a number of days is the product of the average wage of those days and the number of days.
First 7 days:
average wage: $87
number of days: 7
total wages in first 7 days = 7 * $87/day = $609
Last 7 days:
average wage: $92
number of days: 7
total wages in last 7 days = 7 * $92/day = $644
8th day:
wages of the 8th day is unknown, so we let x = wages of the 8th day
total wages of 15 days = (wages of first 7 days) + (wages of 8th day) + (wages of last 7 days)
total wages of 15 days = 609 + x + 644 = x + 1253
average wage for 15 days = (sum of wages for the 15 days)/15
average wage for 15 days = (x + 1253)/15
We are told the average for the 15 days is $90/day.
(x + 1253)/15 = 90
Multiply both sides by 15.
x + 1253 = 1350
Subtract 1253 from both sides.
x = 97
Answer: $97
ANSWER:
-14 1/2
STEP-BY-STEP:
-4 1/7 x 3 1/2 = -14.50
-14.50 turned into the simplest fraction it can be, without changing the whole number, is -14 1/2
Sure, there's such a thing as an isosceles right triangle. It's what you get when you draw the diagonal of a square. It has one right angle (of course) and two 45 degree angles. It's the shape that vexed the Pythagoreans.
<span>In order to determine the value of the numbers, we can set up algebraic equations to solve. For this case, we need to set up two equations since we have two unknown numbers. We do as follows:
let x = first number and y = second number
From the problem statement, we set up equations.
Equation 1 - the numbers have a difference of 0.7
x - y = 0.7
Equation 2 - the numbers have a sum of 1
x + y = 1
Solving for x and y via substitution method,
x - y = 0.7
(1-y) - y = 0.7
1 - 2y = 0.7
-2y = 0.7 - 1 = -0.3
y = 0.15 or 3/20
x - 0.15 = 0.7
x = 0.85 or 17/20
Thus, the two numbers are 0.15 and 0.85.</span>
He rounded it to the nearest hundred, not ten. Ten would be 560.
Hope this helps!
