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3 years ago

How do i simplify this equation?

Mathematics

1 answer:

elixir [45]3 years ago

8 0

Answer:

-6 = m (i'll show my work below)

Step-by-step explanation:

-6(m-7) + 7 = -8m + 37

-6m + 42 + 7 = -8m + 37

-6m + 49 = -8m +37

-37 = -37

-6m + 12 = -8m

+6m = +6m

12 = -2m

/-2 = /-2

-6 = m

You might be interested in

What is the slope of the line through (-7, -2) and (-6, 7)?

Reil [10]

Answer:

$\displaystyle =9$

Step-by-step explanation:

The slope formula is

$\displaystyle \frac{y_2-y_1}{x_2-x_1}$

$\displaystyle y_2=7\\\displaystyle y_1=(-2)\\\displaystyle x_2=(-6)\\\displaystyle x_1=(-7)$

$\frac{7-(-2)}{(-6)-(-7)}=\frac{9}{1}=9$

Therefore, the slope is 9, and the correct answer is 9.

Hope this helps!

8 0

3 years ago

Read 2 more answers

In the series finale of 'Breaking Wind', ratings

Pie

Answer:

3937500

Step-by-step explanation:

People watched last year = x

if ratings were up 125% x increased by x and 25% of x

25% of 10.5 million is 2625000

x increased by itself and 2625000

x*2+2625000 = 10500000

cancel out 2625000 by subtracting to both sides

10500000 - 2625000 = 7875000

x*2 = 7875000

cancel out 2 by dividing 2 on both sides

7875000/2 = 3937500

x = 3937500

4 0

3 years ago

your class of 32 students is divided into fourths to create groups to answer a set of questions together then 1/4 of each group

Alecsey [184]

Answer:

2 students

Step-by-step explanation:

32 students are divided into fourths:

32/4 = 8

Each group has 8 people.

1/4 of the students in each group is the same as dividing 8 into fourths:

8/4 = 2

2 students from each group will go up to the front of the classroom.

Hope this helps :)

3 0

3 years ago

Use Definition 7.1.1, DEFINITION 7.1.1 Laplace Transform Let f be a function defined for t ≥ 0. Then the integral ℒ{f(t)} = ∞ e−

poizon [28]

$f(t)=\begin{cases}\cos t&\text{for }0\le t$

The Laplace transform is then

$\mathcal L_s\{f(t)\}=\displaystyle\int_0^\infty f(t)e^{-st}\,\mathrm dt=\int_0^\pi e^{-st}\cos t\,\mathrm dt$

Let $I$ denote the integral we want to compute. Integrating by parts, setting

$u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt$

$\mathrm dv=\cos t\,\mathrm dt\implies v=\sin t$

gives

$\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\int_0^\pi e^{-st}\sin t\,\mathrm dt$

Integrate by parts again, setting

$u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt$

$\mathrm dv=\sin t\,\mathrm dt\implies v=-\cos t$

Then

$\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\left(-e^{-st}\cos t\bigg|_{t=0}^{t=\pi}-s\int_0^\pi e^{-st}\cos t\,\mathrm dt\right)$

$I=e^{-st}(\sin t-s\cos t)\bigg|_{t=0}^{t=\pi}-s^2I$

$(s^2+1)I=s(e^{-\pi s}+1)$

$I=\dfrac s{s^2+1}(e^{-\pi s}+1)$

7 0

3 years ago

I need answers plzz

swat32

Answer:

Honestly this is a bit easy but

Step-by-step explanation:

just look at the graph and see what letter matches with the other one. The answers are R and C, B and Q(i think, its blurry), D and S, F and E, A and P(its blurry so it might be wrong)PLEASE VOTE 5 STARS AND PRESS THANKS

7 0

3 years ago