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3 years ago

How do i simplify this equation?

Mathematics

1 answer:

elixir [45]3 years ago

8 0

Answer:

-6 = m (i'll show my work below)

Step-by-step explanation:

-6(m-7) + 7 = -8m + 37

-6m + 42 + 7 = -8m + 37

-6m + 49 = -8m +37

-37 = -37

-6m + 12 = -8m

+6m = +6m

12 = -2m

/-2 = /-2

-6 = m

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The graph below represents which system of inequalities?

mamaluj [8]

The graph below represents y < 2 over 3x − 2 | y > 2x + 2 system of inequalities. The answer is letter C. The rest of the choices do not answer teh qustion above

3 0

3 years ago

Read 2 more answers

1. Simplify the expression: 4+36+(10-8)’-3+7 A. 130 B. 100 C. 38 D. 37

Alika [10]

Answer:

The answer isn't in the options anyway I'll write it. the answer is 46.

Step-by-step explanation:

According to BODMAS rule - addition should be done first so

4+36= 40 and -3 +7 = 4 so 40+4 ,= 44

then we should do subtracting so, 10-8 = 2

to conclude we should bring the equation to an end so,

44+2 = 46

HOPE THIS HELPS YOU

6 0

3 years ago

I need help with 17, 19, 21, and 23.

Evgen [1.6K]

17. 2x<16 x=7 or lower
All I can help you with is #17,
sorry that I can't answer the other 3.
I hope this helped! :-)

7 0

3 years ago

Read 2 more answers

According to exponent rules,when we divide the expressions we ________ the exponents.

Greeley [361]

Answer:

Subtract

Step-by-step explanation:

According to the Quotient Of Powers Property to divide two powers with the same base, you subtract the exponents.

Ex: 9^12 - 9^9 = 9^3

5 0

3 years ago

URGENT HELP PLEASE!

Vaselesa [24]

Answer:

(a) $x=\dfrac{\pi}{8},\dfrac{3\pi}{8},\dfrac{9\pi}{8},\dfrac{11\pi}{8}$

(b) $x=\dfrac{3\pi}{2},\dfrac{\pi}{6},\dfrac{5\pi}{6}$

Step-by-step explanation:

It is given that $0\leq x\leq 2\pi$ .

(a)

$\sqrt{2}\sin 2x=1$

$\sin 2x=\dfrac{1}{\sqrt{2}}$

$\sin 2x=\dfrac{\pi}{4}$

$2x=\dfrac{\pi}{4},\dfrac{3\pi}{4},\dfrac{9\pi}{4},\dfrac{11\pi}{4}$ $[\because \sin x=\sin y\Rightarrow x=n\pi+(-1)^ny]$

$x=\dfrac{\pi}{8},\dfrac{3\pi}{8},\dfrac{9\pi}{8},\dfrac{11\pi}{8}$

(b)

$\csc^2 x-\csc x-2=0$

$\csc^2 x-2\csc x+\csc x-2=0$

$\csc x(\csc x-2)+1(\csc x-2)=0$

$(\csc x+1)(\csc x-2)=0$

$\csc x=-1\text{ or }\csc x=2$

$\sin x=-1\text{ or }\sin x=\dfrac{1}{2}$ $[\because \sin x=\dfrac{1}{\csc x}]$

$x=\dfrac{3\pi}{2}\text{ or }x=\dfrac{\pi}{6},\dfrac{5\pi}{6}$

Therefore, $x=\dfrac{3\pi}{2},\dfrac{\pi}{6},\dfrac{5\pi}{6}$ .

5 0

3 years ago