If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
Yes 2/4 is less than 2/3 :) I hope this helps
Answer:
Step 1: Distribute
to
and 
Step 2: Subtract from both sides of the equation 
Step 3: Add to both sides of the equation
Step 4: Divide both sides of the equation by 
Step-by-step explanation:
Step 1: Apply the Distributive Property. Then you must distribute
to
and 
Then:

Step 2: You must apply the Subtraction property of Equality and subtract
from both sides of the equation. Then:

Step 3: You must apply the Addition property of Equality and add
to both sides of the equation. Then:

Step 4: You must apply the Division property of Equality and divide both sides by
. Then:

Answer:
We do not know
Step-by-step explanation:
There is no time when the doctor starts from home, so it is technically impossible to solve.