The number of Na atoms in the reactants = 2
<h3>Further explanation</h3>
Every chemical reaction involves compounds that can act as reactants or products
The reactants will react to produce products
The reactants are usually written on the left side of the reaction, while the products on the right side of the reaction
Reaction
2 NaCl + H₂SO₄ → 2 HCl + Na₂SO₄
The element with atomic number 11 = Na(Natrium)
The number of atoms of the element that reacts or is produced can be seen from the reaction coefficient and the number of atoms in the compound
Na in NaCl = 1 atom
From equation, cofficient for NaCl = 2, so number of atoms of Na=2 x 1 = 2
Rydberg formula is given by:
where, = Rydberg constant =
= wavelength
and are the level of transitions.
Now, for = 2 and = 6
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Now, for = 2 and = 5
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Now, for = 2 and = 4
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Now, for = 2 and = 3
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Answer:
We have to add 9.82 grams of calcium acetate
Explanation:
Step 1: Data given
Molarity of the calcium acetate solution = 0.207 M
Volume = 300 mL = 0.300 L
Molar mass calcium acetate = 158.17 g/mol
Step 2: Calculate moles calcium acetate
Moles calcium acetate = molarity * volume
Moles calcium acetate = 0.207 M * 0.300 L
Moles calcium acetate = 0.0621 moles
Step 3: Calculate mass calcium acetate
Mass calcium acetate = moles * molar mass
Mass calcium acetate = 0.0621 moles * 158.17 g/mol
Mass calcium acetate = 9.82 grams
We have to add 9.82 grams of calcium acetate
Molar mass Li2CO3 = 73.89 g/mol
Molar mass Li = 6.94g/mol Li = 6.94*2 = 13.88g
% LI = 13.88/73.89*100 = 18.78% perfectly correct.