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nataly862011 [7]
3 years ago
12

replacing standard incandescent lightbulbs with energy-efficient compact fluorescent lightbulbs can save a lot of energy. Calcul

ate the amount if energy saved over 10 h when one 60 W incandescent lightbulb is replaced with an equivalent 18 W compact fluorescent lightbulb
Chemistry
1 answer:
Fantom [35]3 years ago
8 0
The difference between the wattage is 60-18=42W. The saving in energy over 10 hrs is 10×42=420 watt-hours=0.42kWh
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Which of the following will increase the volume of a gas?
Dmitry_Shevchenko [17]

Answer:

B. Decreasing the pressure applied to the gas molecules

Explanation:

According to Boyle's Law, the pressure of the gas is inversely proportional to the volume of the gas. So, the option B is correctly implied to it.

Other values such as Temperature, Number of molecules are inversely proportional to the volume of the gas.

Size of the gas molecules is negligible as compared to volume.

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3 years ago
Which of these is not an example of a biotic part of the ecosystem? a. grass b. birds c. insects d. weather
Natasha_Volkova [10]
Weather. I'm pretty sure.
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14. Compare between the plasticity of edge and screw dislocations in BCC metals 15. Why does a screw dislocation in a BCC metal
Alenkasestr [34]

Answer:

14) The edge dislocation is more plastic than the screw dislocation

15) So as to form kinks that are fast moving

Explanation:

14) Edge and screw dislocations are the two main types of mobile dislocations

The three dimensional core of the screw dislocation prevents the slipping of the layers (one over the other) in a BCC metal such that kinks are required to be formed first  by thermal activation (heating) in order. The kinks are edge dislocation that move such that the screw dislocation moves forward

Hence, the edge dislocation is more plastic than the screw dislocation

15) The three dimensional structure of a screw dislocation acts like a wedge which resists the slipping of the layers in the BCC structure such that the screw dislocation needs to be highly thermally activated forming kinks before the surrounding layers can move.

4 0
3 years ago
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Mariulka [41]
2) generating power by using fossil fuels is harvesting a non-renewable resource. The more you harvest = the less you have
8 0
3 years ago
f the Ksp for HgBr2 is 2.8×10−14, and the mercury ion concentration in solution is 0.085 M, what does the bromide concentration
goldfiish [28.3K]

Answer:

0.057 M

Explanation:

Step 1: Given data

Solubility product constant (Ksp) for HgBr₂: 2.8 × 10⁻⁴

Concentration of mercury (II) ion: 0.085 M

Step 2: Write the reaction for the solution of HgBr₂

HgBr₂(s) ⇄ Hg²⁺(aq) + 2 Br⁻

Step 3: Calculate the bromide concentration needed for a precipitate to occur

The Ksp is:

Ksp = 2.8 × 10⁻⁴ = [Hg²⁺] × [Br⁻]²

[Br⁻] = √(2.8 × 10⁻⁴/0.085) = 0.057 M

7 0
3 years ago
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