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fenix001 [56]
3 years ago
10

Help please..............

Mathematics
2 answers:
rosijanka [135]3 years ago
6 0
B: (f=g)(x)=-2x² - 2x +8  is correct
Alex777 [14]3 years ago
5 0
The answer is rather symbol just combine the like terms! -2X^2 has no like terms for it is the only exponent so cancel out C because it doesn't start with -2X^2. Next we add all variables with X but no exponent so 3X and -5x Add those together to get 3X +-5X which is -2X because the + is cancelled out so ghe equation is 3X-5X which equals -2X so get rid of everything but B. Finally to confirm it is B add all the basic numbers so the five and three to get eight. So (f+g)(x) = -2X^2 -2X + 8. The answer is B. (You guys said it was A so I changed it but now I know I am right.)
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Explain how you can use base 10 blocks to find one. 54+2.37
jasenka [17]
So you mean add 54+2.37? Well, I do know that the answer to 53+2.37= 2.90. I hope I helped, even if I only helped by an inch.
6 0
3 years ago
Solve for d.<br> d+ 4 = 16.21<br> d=
lutik1710 [3]

Answer:

d = 12.21

Step-by-step explanation:

1) Subtract 4 from both sides.

d = 16.21 - 4

2) Simplify 16.21 - 4 to 12.21.

d = 12.21

Check the answer!

⇒ d + 4 = 16.21

1. Let d = 12.21.

⇒ 12.21 + 4 = 16.21

2. Simplify 12.21 + 4 to 16.21

16.21 = 16.21

Done!

Thanks,

Eddie

8 0
1 year ago
En la fábrica de Don Toño hoy fabricaron 320 pantalones, si los guardan en cajas donde caben 50 ¿cuántas cajas llenaron?
Scrat [10]

Answer:

6.4 Cajas

Step-by-step explanation:

320/50 = 6.4 Cajas

8 0
3 years ago
Five notebooks cost $20. At this rate, how much would 2 notebooks cost
fenix001 [56]
2 notebooks* ($20/ 5 notebooks)= $8.
(Note that the unit cancels out so you get the answer)

Final answer: $8~
4 0
3 years ago
Can you please find the zeros for<br> F(x)=2x^4+17x^2+8?
harina [27]
2x⁴+17x²+8

Let X = x²     →→(x = + or -√X )

The quadratic becomes : 2.X² + 17.X + 8. Now solve for X:

X' = [-b+√(b²-4ac)]/2a             and      X" = [-b-√(b²-4ac)]/2a   
Plug I the values of a, b and c and you will find;

X' = -1/2   and X" = - 8
Since X = √x → →X' = √( -1/2) [imaginary roots]
and X" = √-8 →→ X" = 2√-2  [imaginary roots]
Then:

1st ROOT: X' = - √1/2.i  
2nd ROOT: X" = + √1/2.i
3rd ROOT: X" = + 2√2.i
4th ROOT: X" = - 2√2.i


4 0
3 years ago
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