Answer:
1.) Exponential Growth
2.) Exponential Decay
3.) Exponential Growth
4.) Exponential Decay
Step-by-step explanation:
<u>1.) </u><u><em>f (x) </em></u><u>= 0.5 (7/3)^</u><u><em>x</em></u>
↓
always increasing
<u>2.) </u><u><em>f (x) </em></u><u>= 0.9 (0.5)^</u><u><em>x</em></u>
<em> </em>↓
always decreasing
<u>3.) </u><u><em>f (x) </em></u><u>= 21 (1/6)^</u><u><em>x</em></u>
↓
always increasing
<u>4.) </u><u><em>f (x) </em></u><u>= 320 (1/6)^</u><u><em>x</em></u>
<em> </em> ↓
always decreasing
<u><em>EXPLANATION:</em></u>
It's exponential growth when the base of our exponential is bigger than 1, which means those numbers get bigger. It's exponential decay when the base of our exponential is in between 1 and 0 and those numbers get smaller.
Answer:
![\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D)
Step-by-step explanation:
We are required to simplify the quotient: ![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D)
Since the <u>numerator and denominator both have the same root index</u>, we can therefore say:
![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}} =\sqrt[3]{\dfrac{60} {20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D%20%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B60%7D%20%7B20%7D%7D)
![=\sqrt[3]{3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%7D)
The simplified form of the given quotient is .
Answer:
2112 Steps
Step-by-step explanation:
Answer:The percentage of bottles expected to have a volume less than 32 or is 40.13%
Step-by-step explanation: The volumes of soda in quart soda bottles can be represented by a Nomal model with a= 32.3 oz
b=1.2 oz
Let S be the volume of randomly selected soda bottles
Y-score: S-a/b
For S=32 oz
Substitute the values of S,a and b into the equation
Y=32-32.3/1.2
Y=-0.25
Probability of bottles that have a volume less than 32 oz is
P(S<32)=P(Y<-025)= 0.40129
Percentage of bottles that have volume less than 32 oz will be
0.40127×100%=40.13%
