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avanturin [10]
3 years ago
12

Calculate the theoretical yield of glycolysis and complete glucose breakdown

Chemistry
1 answer:
rusak2 [61]3 years ago
6 0
Eukaryotic cells, the theoretical maximum yield of ATP generated per glucose is 36 to 38, depending on how the 2 NADH generated in the cytoplasm during glycolysis enter the mitochondria and whether the resulting yield is 2 or 3 ATP per NADH
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A _________ is an oxidizing agent that, when mixed with an oxidation hair color, supplies the necessary oxygen gas to develop co
Nezavi [6.7K]

Answer:

Developer

Explanation:

A <u><em>developer </em></u>is an oxidizing agent that, when mixed with an oxidation hair color, supplies the necessary oxygen gas to develop color molecules and create a change in hair color.

Mostly hair colors are used to dye the gray hairs. Hair colors are mixed with developer which is act as oxidizing agent. The wisely used developer is hydrogen peroxide. The hair color is made of ammonia and oxidative tints.

These tints consist of small precursors of uncolored dye. These combined with hydrogen peroxide and form large tint molecule. These are then diffuse into cortex of hair and can not get off during shampoo.

These are termed as permanent hair colors.

3 0
4 years ago
Intermolecular forces allow which of the following substances to be the least fluid?
slava [35]
Out of the options, glass is the least fluid. The proof of this also lies in the fact that glass is the most difficult to melt out of all of the mentioned substances, and melting point gives us a rough estimate of the strength of intermolecular forces.
3 0
4 years ago
Read 2 more answers
Which element is less electronegative than barium
mario62 [17]

<u>Francium</u><u> </u><u>is</u><u> </u><u>less</u><u> </u><u>e</u><u>l</u><u>e</u><u>ctronegative</u><u> </u><u>than</u><u> </u><u>barium</u>

8 0
4 years ago
Read 2 more answers
Many classic experiments have given us indirect evidence of the nature of the atom. Which of the experiments listed below did no
belka [17]

Answer:

The experiment that did not give the results described is e) The Rutherford experiment proved the Thomson "plum-pudding" model of the atom to be essentially correct.

Explanation:

  1. First of all, let's start with the experiment listed in <em>b) The Rutherford experiment was useful in determining the nuclear charge on the atom</em>. This is true, because Rutherford was able to tell through this experiment that the atoms consisted mostly of empty space, with a positively charged nucleus in its center (he was able to tell it was positive because of the deflections observed on the positive alpha particles he used).
  2. Next, we have experiment <em>c) The electric discharge tube proved that electrons have a negative charge</em>. This is also true, given that Thomson was able to correctly determine that there existed particles that were negatively charged, called electrons (he determined this by observing that the rays deviated from the negatively charged plate of the discharge tube in his experiment).
  3. Experiment d) <em>Milikan's oil-drop experiment showed that the charge on any particle was a simple multiple of the charge on the electron</em>, also states the correct results. He was able to determine the charge of many electrically charged droplets of oil, and found out that the charges were a simple multiple of a base value, which he proposed to be that of the negative charge of an electron.
  4. Finally, we take a look at experiment <em>e) The Rutherford experiment proved the Thomson "plum-pudding" model of the atom to be essentially correct</em>. This is the experiment that did not give the result described. In fact, the Rutherford experiment proved that Thomson's "plum-pudding" model was not correct. This is because he determined that atoms consist mostly of empty space, with a dense, positively charged nucleus in its center, surrounded by negatively charged electrons. If Thomson's model were true, Rutherford would have not observed deflected alpha particles in his experiment.
8 0
3 years ago
You have a 1.153 g sample of an unknown solid acid, HA, dissolved in enough water to make 20.00 mL of solution. HA reacts with K
Shalnov [3]

Answer:

The concentration of the unknown acid (HA) is 0.434M

The molar mass of HA is 13.3g/mole

Explanation:

DETERMINATION OF MOLARITY OF THE UNKNOWN ACID

CaVa/CbVb = Na/Nb

From the equation of reaction and at equivalence point, Na = Nb = 1

Therefore, CaVa = CbVb

Va (volume of acid solution) = 20mL = 20/1000 = 0.2L

Cb (concentration of KOH) = 0.715M

Vb (volume of KOH) = 12.15mL

Ca (concentration of acid) = CbVb/Va

Ca = 0.715M × 12.15mL/20mL = 0.434M

DETERMINATION OF MOLAR MASS OF HA

Number of moles of acid = concentration of acid × volume of acid solution in liters = 0.434 × 0.2 = 0.0868mole

Molar mass of HA = mass/number of moles = 1.153g/0.0868mole = 13.3g/mole

7 0
4 years ago
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