Answer:
1.75 moles of H₂O
Solution:
The Balance Chemical Equation is as follow,
N₂H₄ + O₂ → N₂ + 2 H₂O
Step 1: Calculate the Limiting Reagent,
According to Balance equation,
32.04 g (1 mol) N₂H₄ reacts with = 32 g (1 mol) of O₂
So,
28 g of N₂H₄ will react with = X g of O₂
Solving for X,
X = (28 g × 32 g) ÷ 32.04 g
X = 27.96 g of O₂
It means 29 g of N₂H₄ requires 47.96 g of O₂, while we are provided with 73 g of O₂ which is in excess. Therefore, N₂H₄ is the limiting reagent and will control the yield of products.
Step 2: Calculate moles of Water produced,
According to equation,
32.04 g (1 mol) of N₂H₄ produces = 2 moles of H₂O
So,
28 g of N₂H₄ will produce = X moles of H₂O
Solving for X,
X = (28 g × 2 mol) ÷ 32.04 g
X = 1.75 moles of H₂O
To covert from moles to atoms times the number of moles by Avogadro's Number (6.022×10²³)
4.0 × 6.022×10²³ = 2.4088×10^24
The two elements occur in nature as liquids are bromine and mercury.
D.It can not be separated by a physical change.
