Answer: pH = 7.36. The pKa of H2PO4− is 7.21.
Explanation:
Answer:
okay let me know when i can help, ill be happy too help
Answer:
The value of Kc is 9.33 * 10^-17
Explanation:
Step 1: Data given
Temperature = 1000 K
N₂O₄ (g) ⇌ 2 NO₂ (g) Kc = 1.5 * 10^6
N₂ (g) + 2 O₂(g) ⇌ 2 NO₂ (g) Kc = 1.4 * 10^-10
Step 2: Calculate Kc for N₂ (g) + 2 O₂ ⇌ N₂O₄
N₂O₄ (g) ⇌ 2 NO₂ (g) Kc = 1.5 * 10^6
2 NO₂ (g) ⇌ N₂O₄ (g) = 1/Kc = 1 / 1.5 * 10^6 = 6.67 *10^-7
N₂ (g) + 2 O₂(g) ⇌ 2 NO₂ (g) Kc = 1.4 * 10^-10
Kc = Kc1 * Kc2
Kc = (6.67 *10^-7) * (1.4 * 10^-10)
Kc = 9.33 * 10 ^-17
The value of Kc is 9.33 * 10^-17
Answer:
The correct answer is option 3.
Explanation:

The expression of
is given by :
![K_w=[H^+][OH^-]](https://tex.z-dn.net/?f=K_w%3D%5BH%5E%2B%5D%5BOH%5E-%5D)
![K_w\propto [H^+]](https://tex.z-dn.net/?f=K_w%5Cpropto%20%5BH%5E%2B%5D)
![K_w\propto [OH^-]](https://tex.z-dn.net/?f=K_w%5Cpropto%20%5BOH%5E-%5D)
Rise in temperature will result in more dissociation of water molecules into hydrogen ions and hydroxide ions.
With an increase in concentration of hydrogen ions and hydroxide ions value of
will also increase.
Answer:
Mass of barium sulfate = 8.17 g
Explanation:
Given data:
Mass of sodium sulfate = 4.98 g
Mass of barium sulfate produced = ?
Solution:
Na₂SO₄ + Ba(NO₃)₂ → BaSO₄ + 2NaNO₃
Moles of sodium sulfate:
Number of moles = mass/molar mass
Number of moles =4.98 g / 142.04 g/mol
Number of moles = 0.035 mol
Now we will compare the moles pf sodium sulfate and with barium sulfate.
Na₂SO₄ : BaSO₄
1 : 1
0.035 : 0.035
Mass of barium sulfate:
Mass = number of moles × molar mass
Mass = 0.035 mol ×233.4 g/mol
Mass = 8.17 g