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Anastasy [175]
3 years ago
15

Which class of organic compounds contains nitrogen?

Chemistry
1 answer:
Westkost [7]3 years ago
6 0
<span>(3) amina ........................</span>
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Magnesium hydroxide [Mg(OH)2] is an ingredient in some antacids. How many grams of Mg(OH)2 are needed to neutralize the acid in
Allushta [10]

Answer:

1.95g of Mg(OH)2 are needed

Explanation:

Mg(OH)2 reacts with HCl as follows:

Mg(OH)2 + 2 HCl → MgCl2 + 2H2O

<em>Where 1 mole of Mg(OH)2 reacts with 2 moles of HCl</em>

To solve this question we must find the moles of acid. Then, with the chemical equation we can find the moles of Mg(OH)2 and its mass:

<em>Moles HCl:</em>

158mL = 0.158L * (0.106mol / L) = 0.01675 moles HCl

<em>Moles Mg(OH)2:</em>

0.01675 moles HCl * (2mol Mg(OH)2 / 1mol HCl) = 0.3350 moles Mg(OH)2

<em>Mass Mg(OH)2 -Molar mass: 58.3197g/mol-</em>

0.3350 moles Mg(OH)2 * (58.3197g / mol) =

<h3>1.95g of Mg(OH)2 are needed</h3>
3 0
3 years ago
How many molecules are in 20.2 moles of CO₂?
mrs_skeptik [129]

Answer:

1.22 x 10²⁵ molecules CO₂

Explanation:

To find the amount of molecules, you need to multiply the number of moles by Avogadro's Number. Avogadro's Number is a ratio which represents the amount of molecules per every 1 mole. It is important to arrange this ratio in a way that allows for the cancellation of units (since you are going from moles to molecules, moles should be in the denominator). The final answer should have 3 sig figs like the given value.

Avogadro's Number:

6.022 x 10²³ molecules = 1 mole

 20.2 moles CO₂           6.022 x 10²³ molecules
---------------------------  x  --------------------------------------  = 1.22 x 10²⁵ molecules
                                                     1 mole

8 0
1 year ago
If i initially have 4.0 l of a gas at a pressure of 1.1 atm, what will the volume be if i increase the pressure of 3.4 atm?
ddd [48]
  The  volume  of  a  gas  that   its  pressure  increase  to  3.4  atm   is    calculated  as   follows

  By  use  of  boyles   law   that  is  P1V1=P2V2
V1=4.0  L
P1=1.1  atm
P2=3.4  atm
V2= P1V1/P2  

(1.1  atm  x  4.0 L)/3.4  atm=  1.29  L
4 0
2 years ago
Give explanations for the large drops in melting point from C to Si and from Ge to Sn.
____ [38]

As we move down the group, the metallic bond becomes more stable and the formation of forming covalent bond decreases down the group due to the large size of elements.

Covalent and metallic bonding leads to higher melting points. Due to a decrease in attractive forces from carbon to lead there is a drop in melting point.

Carbon forms large covalent molecules than silicon and hence has a higher melting point than silicon.

Similarly, Ge also forms a large number of covalent bonds and has a smaller size as compared to that of Sn. Hence melting point decreases from Ge to Sn.

The order will be C>Si>Ge>Pb>Sn.

To learn more about the covalent bond, visit: brainly.com/question/10777799

#SPJ4

3 0
1 year ago
Which of the following statements best explains the observation that hydrogen fluoride has the highest boiling point of all the
olasank [31]

Answer:

c. HF can participate in hydrogen bonding.

Explanation:

<u>The boiling points of substances  often reflect the strength of the </u><u>intermolecular forces</u><u> operating among the molecules.</u>

If it takes more energy to  separate molecules of HF than of the rest of the hydrogen halides because HF molecules are held  together by stronger intermolecular forces, then the boiling point of HF will be higher than  that of all the hydrogen halides.

A particularly strong  type of intermolecular attraction is called the hydrogen bond, <em>which is a special type of dipole-dipole interaction between the hydrogen atom in a polar bond</em>, such as N-H, O-H, or F-H, and an electronegative O, N, or F atom.

7 0
3 years ago
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