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3 years ago

Which statement correctly describes the relationship between △RST and △R’S’T?

Mathematics

1 answer:

Vinil7 [7]3 years ago

8 0

<span>The answer is the third statement. "The triangles are congruent because triangle R'S'T' is a rotation of triangle RST and rotation in a rigid motion" The triangles are congruent because the image is a rotation (There is a rotation of 180 degrees) of the original and a rotation is a rigid motion. The best way to test it out is to assign values to the points for points R, S, and T and then apply the rule to see where the new image will be. </span>

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Can someone please help me on this?

xz_007 [3.2K]

Answer:

The surface area of the green prism is 2.5 times greater than the surface area of the blue prism

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2 years ago

State whether each equation is true or false. For each equation that is true, write the number property shown by the equation.

mylen [45]

Step-by-step explanation:

a. true

property: identity

b. false

property: communitive

c. true

associative

d. false

property: multiplication property of zero

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3 years ago

F(x) = 4x^2 - 3x + 2kx + 1

dybincka [34]

$f(x)=4x^2-3x+2kx+1=4x^2+(2k-3)x+1\\\\a=4;\ b=2k-3;\ c=1\\\\function\ has\ two\ zeros\ when\ \Delta=b^2-4ac > 0\\\\\Delta=(2k-3)^2-4\cdot4\cdot1=4k^2-12k+9-16=4k^2-12k-7 > 0\\\\a_k=4;\ b_k=-12;\ c_k=-7\\\\\Delta_k=(-12)^2-4\cdot4\cdot(-7)=144+112=256\\\\k_1=\frac{-b_k-\sqrt{\Delta_k}}{2a_k};\ k_2=\frac{-b_k+\sqrt{\Delta_k}}{2a_k}$

$\sqrt{\Delta_k}=\sqrt{256}=16\\\\k_1=\frac{12-16}{2\cdot4}=\frac{-4}{8}=-\frac{1}{2};\ k_2=\frac{12+16}{2\cdot4}=\frac{28}{8}=\frac{7}{2}\\\\a_k=4 > 0\ (up\ parabola\ arms-see\ the\ picture)\\\\Answer:k\in(-\infty;-\frac{1}{2})\ \cup\ (\frac{7}{2};\ \infty)$

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2 years ago

Find the average rate of change of the function f(x)=(3/-3x-5), on the interval x ∈ [0,3]

Svet_ta [14]

Answer:

The average rate of change on the given interval is 9/70

Step-by-step explanation:

Here, we are to find the average rate of change of the function on the given interval

We proceed as follows;

on an interval [a,b] , we can find the average rate of change using the formula;

f(b) - f(a)/b-a

From the question;

a = 0

b = 3

f(0) = -3/5

f(3) = -3/14

Substituting the values, we have;

-3/14-(-3/5)/3-0

= 3/5-3/14/3

= (42-15)/70/3

= 27/70/3

= 27/70 * 1/3 = 9/70

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2 years ago

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Anit [1.1K]

Yes they are equivalent expressions. If you take the z to the power of two, and subtract that from the other z to the power of two, it is zero. So you are left with four which is the answer

6 0

3 years ago