6x+7 X=3<br> Evaluate the expression

PLEASE ANSWER THIS VERY FAST!! A gym membership costs $40 per month plus a one time sign up fee of $20. How many months would it

vfiekz [6]

Answer:

About 24 months

Step-by-step explanation:

1000-20= 980

980/40= 24.5

4 0

3 years ago

Read 2 more answers

M_6 is (2x – 5)º and m_8 is (x + 5)º.

HACTEHA [7]

m_6 + m_8 = 180º because they form a straight line.

So, (2x-5) + (x+5) = 180

3x = 180

x = 60

So, m_115º (2•60 - 5 = 115)

Also, because the two lines are parallel m_6 = m_3 by alternate interior angles.

So, m_3 = 115º

4 0

2 years ago

Tom is throwing darts at a target. In his last 30 throws, Tom has hit the target 20 times. You want to know the estimated probab

Musya8 [376]

Each scenario can be used to simulate probability, and there are 3 correct scenarios and 2 incorrect scenarios in the list of options

<h3>How to categorize the simulations?</h3>

From the question, we have the following parameters:

Number of throws = 30
Number of hits = 20

This means that the probability of hit is:

P(Hit) = 20/30

Simplify

P(Hit) = 2/3

Using the complement rule,

P(Miss) = 1/3

The above means that the simulation that represents the situation must have the following parameters:

P(Success) = 2/3
P(Failure) = 1/3
Number of experiments = 3

Using the above highlights, the correct scenarios are:

Rolling a die three times with numbers 1 to 4 representing a hit
Spinner a spinner of 3 equal sections three times with two sections representing hit
Spinner a spinner of 6 equal sections three times with four sections representing hit

Read more about probability at:

brainly.com/question/25870256

#SPJ1

6 0

2 years ago

OK right image and easier to read lol

Brums [2.3K]

Answer:

you want us to do all that

Step-by-step explanation:

6 0

3 years ago

Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show

Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is $P(x \ge 60)=0.0901$

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

The number of sample selected is $n= 50,000$

The probability of observing the defect is mathematically evaluated as

$p = \frac{1}{1000}$

$= 0.001$

The probability of not observing the defect is mathematically evaluated as

$q = 1-p$

$= 1-0.001$

$= 0.999$

The mean of this probability is mathematically represented as

$\mu = np$

Substituting values

$\mu = 50000*0.001$

$= 50$

The standard deviation of this probability is mathematically represented as

$\sigma = \sqrt{npq}$

Substituting values

$= \sqrt{50000 * 0.001 * 0.999}$

$= \sqrt{49.95}$

$= 7.07$

the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

in standardizing the normal distribution the normal area used to approximate $P(x \ge 60)$ is the right of 59.5 instead of 60 because x= 60 is part of the observation

The z -score is obtained mathematically as

$z = \frac{x-\mu }{\sigma }$

$= \frac{59.5 - 50 }{7.07}$

$=1.34$

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

The total area under the curve is 1

So

$P(x \ge 60) \approx P(z > 1.34)$