Answer:
The period, in seconds to two decimal places is, 2.84 sec
Step-by-step explanation:
Using formula:
......[1]
where
T represents the Time period in second
l represents the length of the pendulum/
As per the statement:
Use the gravitational constant g = 9.8 m/s^2 , length of the simple pendulum(l) = 2 meters and
Substitute the given values we have;
⇒
Therefore, the period, in seconds to two decimal places is, 2.84 sec
Answer:
the statements are not equivalent
Answer:
use app Gauthmath its will give you the answer
X(3y+2)-6(3y+2)
(x-6)(3y+2)
so the answer is 2+3y
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