The Murphy family spend $ 700
<em><u>Solution:</u></em>
Given that,
<em><u>Murphy family has 4 members and they went to 7 games</u></em>
Let "x" be the cost of each game
Murphy family cost: ![4 \times 7 \times x = 28x](https://tex.z-dn.net/?f=4%20%5Ctimes%207%20%5Ctimes%20x%20%3D%2028x)
<em><u>Chen family has 5 members and they went to 4 games</u></em>
Chen family cost: ![5 \times 4 \times x = 20x](https://tex.z-dn.net/?f=5%20%5Ctimes%204%20%5Ctimes%20x%20%3D%2020x)
<em><u>In total, the two families spent $1200</u></em>
Therefore,
28x + 20x = 1200
48x = 1200
Divide both sides by 48
x = 25
<em><u>How much did the Murphy family spend?</u></em>
Murphy family cost = 28x = 28(25) = 700
Thus murphy family spend $ 700
We can use prime factorization to find the GCF:
![12 = 3^1 \cdot 4^1](https://tex.z-dn.net/?f=%2012%20%3D%203%5E1%20%5Ccdot%204%5E1%20)
![20 = 4^1 \cdot 5^1](https://tex.z-dn.net/?f=%2020%20%3D%204%5E1%20%5Ccdot%205%5E1%20)
The greatest value both 12 and 20 share is 4. By factoring this out of the equation, we get:
4(3 + 5) = 4(8) = 32
Answer: Srry if I'm wrong 252
Step-by-step explanation:
10 x 6= 60
8 x 12= 96
8 x 12= 96
10 x 11= 110
60 + 96 + 96 +110= 252.
Also I use the same platform for my school