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marusya05 [52]
3 years ago
14

10. Which of these is NOT a perfect square? a. 81 b. 100 C. X2 d. 42

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
5 0

Answer: 42 is not a square of a whole number

Step-by-step explanation: 81= 9², 100= 10², x²= x·x, 6²= 36 and 7²= 49

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2 years ago
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Suppose x, y and z are integers. Prove that, if 3x−y + 5z is even, then at least one of x, y or z is even.
Elden [556K]

Given:

x, y and z are integers.

To prove:

If 3x-y+5z is even, then at least one of x, y or z is even.

Solution:

We know that,

Product of two odd integers is always odd.          ...(i)

Difference of two odd integers is always even.          ...(ii)

Sum of an even integer and an odd integer is odd.      ...(iii)

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3x is always odd.          [Using (i)]

5z is always odd.          [Using (i)]

3x-y is always even.       [Using (ii)]

(3x-y)+5z is always odd.       [Using (iii)]

3x-y+5z is always odd.

So, out assumption is incorrect.

Thus, at least one of x, y or z is even.

Hence proved.

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