Answer:
New pressure P2 = 4.95 atm
Explanation:
Given:
Old volume V1 = 1.50 L
New volume V2 = 0.50 L
Old pressure P1 = 1.65 atm
Find:
New pressure P2
Computation:
P1V1 = P2V2
So,
(1.50)(1.65) = (0.50)(P2)
New pressure P2 = 4.95 atm
Answer:
0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.
Explanation:
Mass percentage of oxalic acid = 5.50%
This means that in 100 grams of solution there are 5.50 grams of oxalic acid.
Mass of solution , m = 100
Volume of the solution = V
Density of the solution = d = 1.024 g/mL
V = 97.66 mL = 0.09766 L
(1 mL = 0.001 L)
Moles of oxalic acid = 
The molarity of the solution :
0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.
Answer:
She could prove that it is a combination of substances by looking for a change in color, or the formation of bubbles. She could also try to pull the combination apart by physical means alone.
Explanation:
Answer:
The molecular formula of X is C8H9NO2
Explanation:
Step 1: Data given
exact mass of 151.0640
Molar mass of C = 12 g/mol
Molar mass of H = 1.00783 g/mol
Molar mass of O = 15.9949 g/mol
Molar mass of N = 14.0031 g/mol
Step 2: Calculate molar mass of C7H5NO3
7*12 + 5*1.00783 + 14.0031 + 3*15.9949 = 151.02695 g/mol
Step 3: Calculate molar mass of C8H9NO2
8*12 + 9*1.00783 + 14.0031 + 2*15.9949 = 151.06337 g/mol
Step 4: Calculate molar mass of C10H17N
10*12 + 17*1.00783 + 14.0031 = 151.13621 g/mol
The molecular formula of X is C8H9NO2
