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Papessa [141]
3 years ago
9

QUE NOMBRE RECIBE LA MASA GASEOSA QUE ENVUELVE LA TIERRA

Chemistry
1 answer:
Keith_Richards [23]3 years ago
4 0

Answer:NO SE

Explanation:

LEL

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What is an example of potential energy and kentic energy?
lana [24]
Potential energy is stored energy. Kinetic energy involves movement.

If a ball is on the top of a hill, it has the most potential energy on the very top of the hill. The kinetic energy is also 0 at this point.

If the ball rolls down the hill, potential energy decreases while kinetic increases.

simple example
3 0
4 years ago
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Can someone please answer Convert the following to moles (1-4) questions with explanation
damaskus [11]

Answer:

1 ) 0.274 mol N2

2 ) 5.847 mol KNO3

yea... im just gonna do two fo them, i think u can figure it out from there

Explanation:

4 0
3 years ago
Adding hydrogen atoms to an unsaturated fatty acid will make it __________.
xxMikexx [17]

The answer is (a.) more solid

 

Adding hydrogen atoms to an unsaturated fatty acid will make it more solid. This process is called hydrogenation. In this process, hydrogen is added to an unsaturated fatty acid to make it more saturated and thereby more solid at a room temperature.

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3 years ago
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An analytical chemist is titrating of a solution of propionic acid with a solution of 224.9 ml of a 0.6100M solution of propioni
Svetllana [295]

<u>Answer:</u> The pH of acid solution is 4.58

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}    .....(1)

  • <u>For KOH:</u>

Molarity of KOH solution = 1.1000 M

Volume of solution = 41.04 mL

Putting values in equation 1, we get:

1.1000M=\frac{\text{Moles of KOH}\times 1000}{41.04}\\\\\text{Moles of KOH}=\frac{1.1000\times 41.04}{1000}=0.04514mol

  • <u>For propanoic acid:</u>

Molarity of propanoic acid solution = 0.6100 M

Volume of solution = 224.9 mL

Putting values in equation 1, we get:

0.6100M=\frac{\text{Moles of propanoic acid}\times 1000}{224.9}\\\\\text{Moles of propanoic acid}=\frac{0.6100\times 224.9}{1000}=0.1372mol

The chemical reaction for propanoic acid and KOH follows the equation:

                 C_2H_5COOH+KOH\rightarrow C_2H_5COOK+H_2O

<u>Initial:</u>          0.1372         0.04514  

<u>Final:</u>           0.09206          -                0.04514

Total volume of solution = [224.9 + 41.04] mL = 265.94 mL = 0.26594 L     (Conversion factor:  1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{salt}]}{[acid]})

pH=pK_a+\log(\frac{[C_2H_5COOK]}{[C_2H_5COOH]})

We are given:  

pK_a = negative logarithm of acid dissociation constant of propanoic acid = 4.89

[C_2H_5COOK]=\frac{0.04514}{0.26594}

[C_2H_5COOH]=\frac{0.09206}{0.26594}

pH = ?  

Putting values in above equation, we get:

pH=4.89+\log(\frac{(0.04514/0.26594)}{(0.09206/0.26594)})\\\\pH=4.58

Hence, the pH of acid solution is 4.58

7 0
4 years ago
A 4Kg rock is rolling 10m/s find it’s kinetic energy
Lubov Fominskaja [6]
KE=.5mv^2
M=mass
v=velocity
.5(4)(100)=200
That should be the answer.
5 0
3 years ago
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