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krek1111 [17]
3 years ago
5

How are scientific questions answered?

Chemistry
1 answer:
galben [10]3 years ago
3 0

Answer:

D

Explanation:

Scientists always perform tests and observe and measure in the physical world to prove their points or answer their questions.

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A gas exerts a pressure of 0.62 atm. Convert this to kPa and mmHg. Be sure to show your work.
IRINA_888 [86]

Answer:

The answer to your question is 0.62 atm = 62.82 kPa = 471.2 mmHg

Explanation:

Data

P = 0.62 atm

P = ? kPa

P = ? mmHg

Process

1.- Look for the conversion factor of atm to kPa and mmHg

 1 atm = 101.325 kPa

1 atm = 760 mmHg

2.- Do the conversions

                  1 atm ----------------- 101.325 kPa

                  0.62 atm ------------  x

                   x = (0,62 x 101.325) / 1

                  x = 62.82 kPa

                   1 atm ------------------ 760 mmHg

                   0.62 atm ------------  x

                   x = (0.62 x 760)/1

                   x = 471.2 mmHg                

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. Consider the following half-reactions:
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d. Fe(s) and Al(s)

<h3>Further explanation</h3>

In the redox reaction, it is also known  

Reducing agents are substances that experience oxidation  

Oxidizing agents are substances that experience reduction

The metal activity series is expressed in voltaic series  

<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au  </em>

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent  

The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent

So that the metal located on the left can push the metal on the right in the redox reaction  

The electrodes which are easier to reduce than hydrogen (H), have E cells = +

The electrodes which are easier to oxidize than hydrogen have a sign E cell = -

So the above metals or metal ions will reduce Pb²⁺ (aq) will be located to the left of the Pb in the voltaic series or which have a more negative E cell value (greater reduction power)

The metal  : d. Fe(s) and Al(s)

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