Answer:
2 is the required answer.
Step-by-step explanation:
<u>Solution:</u>
<u>Given</u><u>:</u>
-5x+3y=2..............(i)
Putting the value of y=2x in the equation (i); we get:
i.e -5x+3×2x=2
or, -5x+6x=2
or, x=2
i.e. x=2
y=2x=2×2=4
9514 1404 393
Answer:
a) E = 6500 -50d
b) 5000 kWh
c) the excess will last only 130 days, not enough for 5 months
Step-by-step explanation:
<u>Given</u>:
starting excess (E): 6500 kWh
usage: 50 kWh/day (d)
<u>Find</u>:
a) E(d)
b) E(30)
c) E(150)
<u>Solution</u>:
a) The exces is linearly decreasing with the number of days, so we have ...
E(d) = 6500 -50d
__
b) After 30 days, the excess remaining is ...
E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days
__
c) After 150 days, the excess remaining would be ...
E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system
The supply is not enough to last for 5 months.
Answer:
y=6x is the answer
Step-by-step explanation:
