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3 years ago

Solve 4x= If x=10 HURRY PLEASE ITS A TEST

Mathematics

2 answers:

Aleksandr-060686 [28]3 years ago

8 0

Answer: 40

Step-by-step explanation:

serious [3.7K]3 years ago

4 0

Answer:

Step-by-step explanation:

4(10)

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The linear equation y = 400 + 50x represents the total cost, y , per hour, x , for a lawyer at a law firm. The lawyer charges a

earnstyle [38]

Answer:

453

Step-by-step explanation:

because we multiply the value with the equation

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2 years ago

Estimate the product. Solve using an area model and the standard algorithm. Remember to express your products in standard form.

snow_tiger [21]

Answer:

Step-by-step explanation:

Using the area model and standard algorithm, we have:

332 (tenths)

× 21

332

664

6972 tenths = 697.2

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33.2 × 21 = 30 × 1 = 30

8 0

3 years ago

Evaluate 2.5(8.6/2)-1.8

777dan777 [17]

Step-by-step explanation:

Given the expression:

$2.5( \frac{8.6}{2} ) - 1.8$

Follow BODMAS rule.

always evaluate brackets first, followed by multiply or division then addition or subtraction from LEFT to RIGHT.

$2.5( \frac{8.6}{2} ) - 1.8 \\ = 2.5(4.3) - 1.8 \\ = 10.75 - 1.8 \\ = 8.95$

3 0

3 years ago

The price of a new car was $22,800vin April. However, the price of the car was reduced 5% in May. Find the price in May.

Levart [38]

Answer: 1140

Step-by-step explanation: Sorry if its wrong

3 0

3 years ago

Read 2 more answers

Please help me with geometry

spayn [35]

For each sub-problem shown below, I'm using the distance formula to compute the distance between the two points

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For the points (-10,2) and (-2,2), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((-2-(-10))^2+(2-2)^2)

d = sqrt((-2+10)^2+(2-2)^2)

d = sqrt((8)^2+(0)^2)

d = sqrt(64+0)

d = sqrt(64)

d = 8

------------------------------------------------------

For the points (-3,-1) and (5,1), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-(-3))^2+(1-(-1))^2)

d = sqrt((5+3)^2+(1+1)^2)

d = sqrt((8)^2+(2)^2)

d = sqrt(64+4)

d = sqrt(68)

------------------------------------------------------

For the points (-3,-2) and (1,3), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((1-(-3))^2+(3-(-2))^2)

d = sqrt((1+3)^2+(3+2)^2)

d = sqrt((4)^2+(5)^2)

d = sqrt(16+25)

d = sqrt(41)

------------------------------------------------------

For the points (-3,-5) and (-2,-4), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((-2-(-3))^2+(-4-(-5))^2)

d = sqrt((-2+3)^2+(-4+5)^2)

d = sqrt((1)^2+(1)^2)

d = sqrt(1+1)

d = sqrt(2)

------------------------------------------------------

For the points (0,0) and (5,5), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-0)^2+(5-0)^2)

d = sqrt((5)^2+(5)^2)

d = sqrt(25+25)

d = sqrt(50)

------------------------------------------------------

For the points (1,2) and (1,-10), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((1-1)^2+(-10-2)^2)

d = sqrt((0)^2+(-12)^2)

d = sqrt(0+144)

d = sqrt(144)

d = 12

------------------------------------------------------

For the points (1,2) and (5,2), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((5-1)^2+(2-2)^2)

d = sqrt((4)^2+(0)^2)

d = sqrt(16+0)

d = sqrt(16)

d = 4

------------------------------------------------------

For the points (2,3) and (10,9), the distance is...

d = sqrt((x2-x1)^2+(y2-y1)^2)

d = sqrt((10-2)^2+(9-3)^2)

d = sqrt((8)^2+(6)^2)

d = sqrt(64+36)

d = sqrt(100)

d = 10

------------------------------------------------------

See the attached image for how the answers match up (take note of the letter labels)

3 0

3 years ago