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kow [346]
3 years ago
10

Solve 4x= If x=10 HURRY PLEASE ITS A TEST

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
8 0

Answer: 40

Step-by-step explanation:

serious [3.7K]3 years ago
4 0

Answer:

40

Step-by-step explanation:

4x

4(10)

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A stock was priced at $12 3/8 per share. It rose in price by $3 1/4 per share. What was its new price?
lubasha [3.4K]

Option A

The new price is $ 15 \frac{5}{8}

<h3><u>Solution:</u></h3>

Given that, a stock was priced at $ 12 \frac{3}{8} per share.

It rose in price by $ 3 \frac{1}{4} per share.

New price = old price + rise in price

Thus to find out the new price, we have to add old price and rise in price

\text { So, new price }=\$ 12 \frac{3}{8}+\$ 3 \frac{1}{4}

\text { New price }=\frac{12 \times 8+3}{8}+\frac{3 \times 4+1}{4}

On solving we get,

\text { New price }=\frac{96+3}{8}+\frac{12+1}{4}

\begin{array}{l}{\text { New price }=\frac{99}{8}+\frac{13}{4}=\frac{99+26}{8}} \\\\ {\text { New price }=\frac{125}{8}}\end{array}

On converting to mixed fraction,

\begin{array}{l}{\text { New price }=\frac{120+5}{8}} \\\\ {\text { New price }=15 \frac{5}{8}}\end{array}

Hence, the new price is 15 \frac{5}{8}, so option A is correct.

8 0
4 years ago
A population of deer inside a park has a carrying capacity of 200 and a growth rate of 3%. If the initial population is 80 deer,
otez555 [7]

Answer:

The population of deer at any given time = 200(e^0.03t)  ÷ (1.5 + (e^0.03t))

Step-by-step explanation:

This is an example of logistic equation on population growth

carrying capacity, k = 200

Rate, r = 3% = 0.03

Initial Population, P1 =  80

P(t) =?

P(t) = (P1 (k)(e^rt)) ÷ (k- P1 + P1(e^rt))

P(t) = (80 (200)(e^0.03t)) ÷ (200 - 80 + 80(e^0.03t))

     = (16000(e^0.03t))  ÷ (120 + 80(e^0.03t))

      = 200(e^0.03t)  ÷ (1.5 + (e^0.03t))

8 0
3 years ago
If 9 is added to twice a number and this sum is multiplied by 2​, the result is the same as if the number is multiplied by negat
bagirrra123 [75]
Let the number be x
(9+2x)×2= (-3x)+4
18+4x=-3x+4
4x+3x=4-18
7x=-14
x=-2
8 0
3 years ago
How many 4-letter passords can be made using the letters A thought Z if...
mezya [45]

Answer:

a.)The total 4-letters passwords when repetition of letters is allowed are 456976

b.)The total 4-letters passwords when repetition of letters is not allowed are 358800

Step-by-step explanation:

Some situations of <em>probability</em> involve multiple events. When one of the events affects others, they are called dependent events. For example, when objects are chosen from a list or group and are not returned, the first choice reduces the options for future choices.

There are two ways to sort or combine results from dependent events. <em>Permutations</em> are groupings in which the order of objects matters. <em>Combinations</em> are groupings in which content matters but order does not.

How many 4-letter passwords can be made using the letters A throught Z if...

a)Repetition of letters is allowed?

There are only 26 possible values for each letter of the password (The English Alphabet consists of 26 letters). The total 4-letters passwords when repetition of letters is allowed are 26^{4} =456976

b) Repetition of letters is not allowed?

If repetition of  letters is not allowed, we can only choose 4 letters out of 26. Using the permutation equation nP_{k} =\frac{n!}{(n-k)!}

The total 4-letters passwords when repetition of letters is not allowed are 26P_{4} =\frac{26!}{(26-4)!}=26.25.24.23=358800

.

7 0
3 years ago
ssri has a bag containing 6 half dollars and 5 dollar coins. What is the total mass of coins in saris bag ,half dollar 11.34 and
Lelu [443]

Answer:

19.44??

Step-by-step explanation:

8 0
3 years ago
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