If u raise a power to another power, then u multiply the powers. In this case, u can simplify to 6^2p =6^10
Now you have like bases, so you can set the powers equal to each other. So now, 2p=10. Now p=5
<h2>y + 1 = -3(x - 10)</h2>
Here's the formula:
y - y1 = m(x - x1)
Substitute numbers accordingly:
y1: so 1 goes in the y1 spot (you switch the signs because it was already negative)
x1: and 10 goes to the x1 spot
m: -3 belongs in m
Hello,
x^2-y^2=(x+y)(x-y)
x^3-y^3=(x-y)(x²+xy+y²)
Let's use Horner's division
.........|a^3|a^2.|a^1..........|a^0
.........|1....|5....|6..............|8....
a=p...|......|p....|5p+p^2....|6p+5p^2+p^3
----------------------------------------------------------
.........|1....|5+p|6+5p+p^2|8+6p+5p^2+p^3
The remainder is 8+6p+5p^2+p^3 or 8+6q+5q^2+q^3
Thus:
8+6p+5p^2+p^3 = 8+6q+5q^2+q^3
==>p^3-q^3+5p^2-5q^2+6p-6p=0
==>(p-q)(p²+pq+q²)+5(p-q)(p+q)+6(p-q)=0
==>(p-q)[p²+pq+q²+5p+5q+6]=0 or p≠q
==>p²+pq+q²+5p+5q+6=0
And here, Mehek are there sufficients explanations?
Answer:
c = 10/n + 2
Step-by-step explanation:
