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Ilya [14]
3 years ago
8

Please help! Question above

Mathematics
2 answers:
notsponge [240]3 years ago
8 0
The answer is the first one

Lina20 [59]3 years ago
8 0
This answer is letter A.
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At her archery lessons, Tess has a 90% chance of getting a bull's eye. Unfortunately, there is only a 40% chance that her
zepelin [54]

Answer:

Step-by-step explanation

2. you gave that there is a 40% chance that her instructor will be watching, which means that there is a 60% chance he will not be watching (100% - 40%).

3. you gave that there is a 90% chance of making a bull's eye, and 40% chance the instructor will be watching

since those two events are independent of each other, the chance of both of them happening is the product of the two chances, namely 0.9 x 0.4 = 0.36, or 36%

6 0
3 years ago
Please explain how to finish these 3 problems, if you answer them you'll get brainlyist.
stepan [7]
12. (x-√3)(x+1) = x² + (1-√3)x - √3

13. (x+2)(x²+4) = x³ + 2x² + 4x + 8

14. (3x³ + 6x² - 5x + 12) ÷ (x-3)

= [(x - 3)(3x² + 15x + 40) + 132 ] ÷ (x-3)

Quotient = 3x² + 15x + 40
Remainder  = 132

3 0
4 years ago
What is the domain of the function?
balu736 [363]

Answer:

the blue line is at the 7 and the blue line is at -1

6 0
3 years ago
A fair coin is tossed four times. What is the probability that the number of heads appearing on the first two tosses is equal to
alekssr [168]

Answer: 3/8

Step-by-step explanation:

Since it is a fair coin, then generally, P(Head) = P(Tail) = ½

And since we've been asked to find the probability that the number of heads in the first two tosses be equal to the number of heads in the second two tosses, tossing a fair coin four times, the possible outcomes of having equal number of heads in first two tosses and second two tosses becomes:

[HHHH] or [HTHT] or [THTH] or [TTTT] or [HTTH] or [THHT]

=[½*½×½*½] + [½*½×½*½] + [½*½×½*½] + [½*½×½*½] + [½*½×½*½] + [½*½×½*½]

=1/16 * 6

=6/16

=3/8.

8 0
3 years ago
The sum of first three terms of an arithmetic series is 21. If the sum of the first two terms is subtracted from the third term
Ronch [10]

Answer:

The terms are - 1, 7 and 15.

Step-by-step explanation:

Let the terms be a-d, a and a+d

ATQ, a-d+a+a+d=21, a=7. a+d-(a+(a-d))=9. d=8. The terms are - 1, 7 and 15.

5 0
3 years ago
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