Two sets of data are shown.

each year the gardners plant 7/8 of an acre with tomatoes. They sell half of what they grow at a roadside stand. What part of an

Yakvenalex [24]

$\frac78\ \cdot\ \frac12=\frac{7}{16}$

8 0

3 years ago

Read 2 more answers

Answer this pls..................

Sindrei [870]

Answer:

so we know:

total of 20 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry has a total of 14 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14

8 students are in physics

1 2 3 4 5 6 7 8

3 are in all of them

1 2 3

1) underline the main 3

total of 20 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry has a total of 14 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14

8 students are in physics

1 2 3 4 5 6 7 8

2) lets bold the physics students, if you are in physics you have to do chem so that means 8 of the chem students also take physics.

total

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry

1 2 3 4 5 6 7 8 9 10 11 12 13 14

physics

1 2 3 4 5 6 7 8

3) now we bring biology into the "equation"

off the bat we know 3 are definitely in Biology.

so if 4 study ONLY biology we can cross them off our list see the {}

total

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14

physics

1 2 3 4 5 6 7 8

biology

1 2 3 

4) so we have a total of 20 students, 3 in all of the classes (underlined), 8 in physics (bolded). If there 14 in chemistry, 4 take ONLY chemistry {}, 8 take chemistry as well (bolded), that leaves two students, so they must belong in biology. lets italicise them.

total

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14

physics

1 2 3 4 5 6 7 8

biology

1 2 3  13 14

5) out of our total of 20 students we know 14 of the students classes, so the remaining six must be in biology.

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14

physics

1 2 3 4 5 6 7 8

biology

1 2 3 13 14 15 16 17 18 19 20

6) so that was our "diagram" so now lets count how many are in chemistry and biology but NOT physics.

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

-1 2 3 4 5 6 7 8- {9 10 11 12} 13 14

physics

-1 2 3 4 5 6 7 8-

biology

-1 2 3 -13 14 15 16 17 18 19 20

there are 14 students in chemistry and 11 in biology, 5 of them are in both classes so 14-5= 9 and 11-5= 6 9+6=16. BUT 8 of those sixteen are also in -physics- so we arent counting them, we put those students in dashes. so lets count the students out of the dashes. so twelve of them are in chemistry and biology but not physics.

7) so how many are in just biology but not the other classes? lets look at the graph.

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14

physics

1 2 3 4 5 6 7 8

biology

1 2 3 13 14 15 16 17 18 19 20

in the class of biology students 1 2 3 13 and 14 take other classes that leaves students 15 16 17 18 19 and 20. so 6 students take ONLY biology.

sorry its long but i hope this helps!

3 0

3 years ago

Natalie makes $2,000 per month. She spends $100 on credit card payments and $250 on an auto loan. What is her debt-to-income rat

umka2103 [35]

The answer would be 17.5%

3 0

3 years ago

Read 2 more answers

Van purchased a DVD player on sale. The original selling price was $175.80. The sale price was $149.42. What is the first ste

rjkz [21]

Answer:

The percent decrease was 15%

Step-by-step explanation:

In order to find this, use the percent change equation.

(New - Old)/(Old) * 100 = % Change

Now input 149.42 for the New price and 175.80 for the Old price.

(149.42 - 175.80)/(175.80) * 100 = % Change

-26.38/175.80 * 100 = % Change

-.15 * 100 = % Change

-15 = % Change

5 0

3 years ago

2.1 & 2.2 Assessment: Vertex & Standard Form of Quadratic Functions

Brums [2.3K]

$~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill$

$\begin{cases} h=1\\ k=-9 \end{cases}\implies y=a(x-1)^2 - 9\qquad \textit{we also know that} \begin{cases} x=2\\ y=-7 \end{cases} \\\\\\ -7=a(2-1)^2-9\implies 2=a(1)^2\implies 2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill {\Large \begin{array}{llll} y=2(x-1)^2 -9 \end{array}} ~\hfill$

6 0

1 year ago