All categories

3 years ago

___________ are reported in the business section of magazines or newspapers, as well as online.

Mathematics

1 answer:

aleksley [76]3 years ago

4 0

Answer:

The stock market values

Step-by-step explanation:

PLS GIVE BRAINLIEST

You might be interested in

a cell phone company charges $80 per month for unlimited talk, text, and data. write an expression to determine the amount you h

Lunna [17]

Answer:

80x

Step-by-step explanation:

If you pay 80 a month then to find the total you have paid after any number of months you would multiply amount times time which in this case is 80

a constant is the a number on its own so in this case there would be none

a coefficient is the number in front of a variable. Since the equation is 80x the coefficient is 80

8 0

3 years ago

As an estimation we are told 5 miles is 8 km.<br> Convert 40 miles to km

k0ka [10]

Answer:

64.3738

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A motorist traveled 311 miles on 12 gallons of gas. To the nearest tenth, how many miles can the motorist travel on one gallon o

Alina [70]

D. 311 divided by 12 = 25.91
The nearest tenth would be 25.9

3 0

3 years ago

Read 2 more answers

You are analyzing the survey results tabulated below. The first survey question (yes/no) is whether the respondent is over 40, a

ankoles [38]

2 because the 2 is the number on the left and can be bad and good and uhh yea

7 0

2 years ago

Read 2 more answers

Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.

Leya [2.2K]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6$

6 0

3 years ago

___________ are reported in the business section of magazines or newspapers, as well as online.​

___________ are reported in the business section of magazines or newspapers, as well as online.