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zhenek [66]
3 years ago
12

I am having trouble with this question, can someone help i labed them 1,2,3, and 4.

Mathematics
2 answers:
Dimas [21]3 years ago
7 0
I’m pretty sure The answers is 3
Ket [755]3 years ago
5 0

Answer:

3

Step-by-step explanation:

because if he turns right 90 he will get to school but if he turns left 90 he might get half way to the golf course. And since it doesn't specify there is no way in knowing which way to turn

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Carol picked 8 quarts of strawberry and paid $10.00 for them. How much did she pay per quart? Write a proportion
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Alessandro and Francesca raced each other home from school. It took Francesca 13/15 as long as Alessandro to run home. Who got h
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A student wants to report on the number of movies her friends watch each week. The collected data are below: 2 14 1 2 0 1 0 2 Wh
Sunny_sXe [5.5K]

The student's friend watch 1.5 movies every week.

Data provided to us {2, 14, 1, 2, 0, 1, 0, 2}.

Number of data values = 8

Sorted or rearranged data {0, 0, 1, 1, 2, 2, 2, 14}

Median of the data provided;

Median is the mid point value of the data provided to us, but as in this case there are 8 data provided (even number of data), we will take the average of the 2 mid values of the data.

Mid Values = 1 and 2

\bold{Median=\dfrac{1+2}{2} = 1.5}

Mean of the data provided;

Mean=\dfrac{Sum\ of\ all\ data\ values}{Number\ of\ data\ values} \\\\Mean= \dfrac{(0+0+1+1+2+2+2+14)}{8}\\\\Mean=2.75

As we know, The data values provided are 0, 1 and 2, and there is 14 as well in the data which is the maximum value in the data provided to us but the value is far from the other data values provided to us. Therefore, the data value 14 is considered to be an outlier.

An outlier is the maximum value that increases the mean, which makes it larger than it should be.

If we were to compute the mean without the outlier,

Mean=\dfrac{Sum\ of\ all\ data\ values}{Number\ of\ data\ values} \\\\Mean= \dfrac{(0+0+1+1+2+2+2)}{7}\\\\Mean=1.1428

Now, we have understood that the mean is sensitive to outlier can be easily manipulated. thus, mean is not the right option to go for in this case.

Therefore, the median value of 1.5 is the right option.

Hence, the student's friend watch 1.5 movies every week.

To know more visit:

brainly.com/question/1363341

3 0
2 years ago
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