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natulia [17]
3 years ago
14

Is a microwave a computer ?explain why or why not

Physics
1 answer:
Airida [17]3 years ago
4 0
The modern definition of a computer suggests a processor chip, a memory bank, a hard drive and some sort of input and output device. Since the microprocessor inside a microwave lacks several of these features, it is not classified as computer
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A ball is kicked and flies from point P to Q following a parabolic path in which the highest point reached is T. The acceleratio
Semenov [28]
After the foot leaves the ball, the acceleration is always downward and is equal to g at all points
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3 years ago
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What is the unit for measuring energy
sdas [7]
This would be called a Joule. The formula for energy is <span>P.E. = mgh (otherwise known as the gravitational force formula, which is energy.) M is the mass in kilograms, and G is the acceleration due to gravity, which is actually (9.</span>8 m / s2<span> at the surface of the earth.) I hope this helps! ~Mia</span>
7 0
3 years ago
To aid in the prevention of tooth decay, it is recommended that drinking water contain 0.800 ppm fluoride, F−. How many grams of
Leviafan [203]

Answer:

2.23 × 10^6 g of F- must be added to the cylindrical reservoir in order to obtain a drinking water with a concentration of 0.8ppm of F-

Explanation:

Here are the steps of how to arrive at the answer:

The volume of a cylinder = ((pi)D²/4) × H

Where D = diameter of the cylindrical reservoir = 2.02 × 10^2m

H = Height of the reservoir = 87.32m

Therefore volume of cylindrical reservoir = (3.142×202²/4)m² × 87.32m = 2798740.647m³

1ppm = 1g/m³

0.8ppm = 0.8 × 1g/m³

= 0.8g/m³

Therefore to obtain drinking water of concentration 0.8g/m³ in a reservoir of volume 2798740.647m³, F- of mass = 0.8g/m³ × 2798740.647m³ = 2.23 × 10^6 g must be added to the tank.

Thank you for reading.

4 0
3 years ago
Which statement is true for objects in dynamic equilibrium?
lakkis [162]

Answer:

The correct answer to the question is objects have zero acceleration.

Explanation:

Before answering the question, first we have to understand dynamic equilibrium .

A body moving with uniform velocity is said to be in dynamic equilibrium if the net external forces acting on the body is zero. Hence, the body is under balanced forces.

If the external forces acting on a body is not balanced, then the body will accelerate which will destroy its equilibrium condition. Hence, the necessary and sufficient condition for a body to be in dynamic equilibrium is that the forces are balanced.

When a body is in dynamic equilibrium, the body moves with uniform velocity along a straight line unless and until it is compelled by some external unbalanced forces.

Hence, the rate of change of velocity or acceleration of the body will be zero.

5 0
4 years ago
Read 2 more answers
A time-dependent but otherwise uniform magnetic field of magnitude B0(t) is confined in a cylindrical region of radius 6.5 cm. I
Papessa [141]

Answer:

The acceleration is   a = 3.45*10^{3} m/s^2

Explanation:

 From the question we are told that

         The radius is  d = 6.5 cm = \frac{6.5}{100} = 0.065 m

           The magnitude of the magnetic field is  B = 5.5 T

           The rate at which it decreases is  \frac{dB}{dt}  = 24.5G/s = 24.5*10^{-4} T/s

             The distance from the center of field is  r = 1.5 cm = \frac{1.5}{100} = 0.015m

  According to Faraday's law

          \epsilon = - \frac{d \o}{dt}

and   \epsilon = \int\limits  {E} \, dl

 Where  the magnetic flux \o = B* A

             E is the electric field  

             dl is a unit length

 So

         \int\limits  {E} \, dl = - \frac{d}{dt} (B*A)

         {E}  l = - \frac{d}{dt} (B*A)

Now l is the circumference of the circular loop formed by the magnetic field and it mathematically represented as  l = 2\pi r

A is the area  of the circular loop formed by the magnetic field and it mathematically represented as  A= \pi r^2

So

    {E}  (2 \pi r)= -  \pi r^2 \frac{dB}{dt}

    E = \frac{r}{2} [ - \frac{db}{dt} ]  

Substituting values  

    E = \frac{0.015}{2} (24*10^{-4})

         E = 3.6*10^{-5} V/m

The negative signify the negative which is counterclockwise

 

  The force acting on the proton is mathematically represented as

                       F_p = ma

        Also       F_p = q E

So

           ma = qE

 Where m is the mass of the the proton which has a value of  m = 1.67 *10^{-27} kg

 q = 1.602 *10^{-19} C

     So

            a =\frac{1.60 *10^{-19} *(3.6 *10^{-5}) }{1.67 *10^{-27}}

               a = 3.45*10^{3} m/s^2

                   

     

               

8 0
3 years ago
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