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4 years ago

Which statement is true for objects in dynamic equilibrium?

Physics

2 answers:

lakkis [162]4 years ago

5 0

Answer:

The correct answer to the question is objects have zero acceleration.

Explanation:

Before answering the question, first we have to understand dynamic equilibrium .

A body moving with uniform velocity is said to be in dynamic equilibrium if the net external forces acting on the body is zero. Hence, the body is under balanced forces.

If the external forces acting on a body is not balanced, then the body will accelerate which will destroy its equilibrium condition. Hence, the necessary and sufficient condition for a body to be in dynamic equilibrium is that the forces are balanced.

When a body is in dynamic equilibrium, the body moves with uniform velocity along a straight line unless and until it is compelled by some external unbalanced forces.

Hence, the rate of change of velocity or acceleration of the body will be zero.

Mamont248 [21]4 years ago

5 0

Answer:

objects have zero acceleration.

Explanation:

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A series RL circuit with L = 3.00 H and a series RC circuit with C = 3.00 F have equal time constants. If the two circuits conta

Tems11 [23]

Answer:

(a) R = 1Ω

(b) τ = 3

Explanation:

The time constants of the given circuits are as follows

$\tau_{RL} = \frac{L}{R}\\\tau_{RC} = RC$

If the two circuits have equal time constants, then

$\frac{L}{R} = RC\\R^2 = \frac{L}{C} = \frac{3}{3} = 1\\R = 1\Omega$

Therefore, the time constant in any of the circuits is

$\tau = RC = 3$

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3 years ago

If Ms. Ramirez drops a watermelon from the top of the second-floor fire escape outside her room, and it takes 1.5 seconds to hit

mamaluj [8]

The velocity of the watermelon as it hits the ground is 14.715 m/s.

Given the data in the question;

Since the Watermelon was dropped from rest,

Initial velocity of the Watermelon; $u = 0m/s$

Time taken for the Watermelon to hit the ground; $t = 1.5s$

We know that, Acceleration due to gravity; $g = 9.81 m/s^2$

Now, we determine the velocity of the watermelon as it hits the ground which is the final velocity.

From the First Equation of Motion:

$v = u + at$

Now, under gravity, acceleration ''a" will Acceleration due to gravity; $g = 9.81m/s^2$ , "v" is the final velocity, "u" is the initial velocity and "t" is the time taken.

So, we substitute our values into the equation

$v = 0m/s\ +\ ( 9.81m/s^2\ * 1.5s )\\\\v = ( 9.81m/s^2\ * 1.5s )\\\\v = 14.715 m/s$

Therefore, the velocity of the watermelon as it hits the ground is 14.715 m/s

Learn more; brainly.com/question/13275688

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4 years ago

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Vedmedyk [2.9K]

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3 years ago

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1.20 Newton force is working on a 250 gram object. What is the acceleration?

Leokris [45]

Answer:

The answer is B

Explanation:

250g = 0.25kg

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3 years ago