The mass of Jupitar is obtained from the calculations as 5.8 * 10^-14 Kg.
<h3>What is the mass of Jupitar?</h3>
There are nine planets in the solar system and the sun lies at the enter of our solar system. This is the heliocentric model of the solar system.
Given that;
T^2 = GMr^3/4π
T = period
G = gravitational constant
r = radius
M = mass of Jupitar
Now;
1 day = 86400 seconds
1.77 days = 1.77 days * 86400 seconds/1 day
= 152928 seconds
Making M the subject of the formula;
M =4πT^2/Gr^3
M = 4 * 3.142 * (152928)^2/6.67 × 10^-11 * (422 × 10^9)^3
M = 2.9 * 10^11/5.0 * 10^24
M = 5.8 * 10^-14 Kg
Learn more about mass of a planet:brainly.com/question/13851553
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Carbon is an important compound on the earth. This is really visible in Carbon Dioxide. The valence electrons are important because they allow many different types of bonds to occur.
R = 10 ohm
I = 5 A
V= IR = 10 x 5 = 50 v
C. Elements
elements are found in periodic table (in 1 box)
Answer:
Natural frequencies of oscillation and typical earthquake frequencies should be different.
Damping on the structure should be large.
Explanation:
The natural frequency of the structure must be different from the typical earthquake frequency, the more different the better. This is because if both frequencies were the same or similar there is a risk that the building will <u>resonate </u>and collapse.
As for the damping, it must have a high value. This so that the building resists earthquakes better and prevents it from moving dangerously, thus damping on the structure should be large.
