To solve this problem we will apply the concept of current defined as the electron charge flow by the number of electrons per second. That is,
I = q*N
Here q is Flow of electric charge in one second and N the number of electron flow per second.
A the same time the power is described as the applied voltage for the current.
P = VI
We know the charge of electron,
Coulombs, then the current is


And the power in the Beam is



1 is c
2 is c
3 is d
4 is b
5 is d
6 is d
7 is a
8 is a
9 is c
10 is d
i hope my answers help you
Answer:
144 cm²
Explanation:
In dividing to 8 cubes the side of a cube will be 2 cm.
It can be taken by volume as
4×4×4 = 8×(l×l×l) where l = length of the cube required.
So surface area of a small cube is 6×(2×2) = 24 cm²
Six such cubes will have a surface area of 144 cm²