There is no solution to this system of linear equations
Answer:
Cameron found 23 quarters and 57 dimes.
Step-by-step explanation:
Let the number of quarters Cameron found = Q
And the number of dimes = D
Since, total number of coins were 80,
Q + D = 80 -----(1)
Total amount of the coins was $11.45,
0.1D + 0.25Q = 11.45
10D + 25Q = 1145
2D + 5Q = 229 -----(2)
Equation (1) multiplied by 2 then subtracted by equation (2),
(2D + 5Q) - 2(Q + D) = 229 - 2(80)
(2D - 2D) + (5Q - 2Q) = 229 - 160
3Q = 69
Q = 23
From equation (1),
23 + D = 80
D = 57
Cameron found 23 quarters and 57 dimes.
First, let's start with the whole number.
Half of 5 is 2.5 or 2 1/2.
4/5 translated into a decimal is 0.8, so half of that would be 0.4.
0.4 translated into a fraction is 2/5.
Add 2 1/2 to 2/5.
I'll show you the long way and the easier way.
The long way is that you find a common denominator for both fractions.
A common denominator would be 10, because you would multiply 2 and 5 (the denominators).
So this would translate the problem into 2 5/10 (Remember that whatever you do to the bottom you have to do to the top) and 4/10.
If you add these together you get 2 9/10.
The easy ways is taking the decimals in the problem (2.5 and 0.8)
Half of 0.8 is 0.4 (As mentioned above).
2.5 + 0.4.
This equals 2.9.