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marissa [1.9K]
2 years ago
8

F(x) = (1/6)^x for x =3

Mathematics
1 answer:
Anastasy [175]2 years ago
5 0

Answer:

1/216 is the answer hope it's right

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When testing for current in a cable with eight ​color-coded wires, the author used a meter to test five wires at a time. How man
balu736 [363]

Answer:

56 different tests

Step-by-step explanation:

Given:

Number of wires available (n) = 8

Number of wires taken at a time for testing (r) = 5

In order to find the number of different tests required for every possible pairing of five wires, we need to find the combination rather than their permutation as order of wires doesn't disturb the testing.

So, finding the combination of 5 pairs of wires from a total of 8 wires is given as:

^nC_r=\frac{n!}{r!(n-r)!}

Plug in the given values and solve. This gives,

^8C_5=\frac{8!}{5!(8-5)!}\\\\^8C_5=\frac{8\times 7\times 6\times 5!}{5!\times 3\times2\times1}\\\\^8C_5=56

Therefore, 56 different tests are required for every possible pairing of five ​wires.

6 0
3 years ago
Please sum 1 help mee​
GarryVolchara [31]

Answer:

Step-by-step explanation:

the green cylinder is 20\pi

while the purple cone is 18\pi

which do you think is more ?  :)

4 0
3 years ago
Read 2 more answers
Select 2 options
madreJ [45]

Answer:

(×-5)(×+1)

×^2+×-5×-5

×^2-4×-5

8 0
3 years ago
Read 2 more answers
Frances walks 15 km west, then turns 90 degrees north and walks 30 km.
Mila [183]
Distance and displacement are 45 km
5 0
3 years ago
A standard letter-sized piece of paper has a length and width of 8.5 inches by 11 inches.
den301095 [7]

Answer:

Area of the resulting rectangle = 23.375 inch²

Step-by-step explanation:

After 1 fold width or length reduces to half.

Area = Length x width

So after 1 fold area will reduce to half.

So we have

              \texttt{Area after n folds =}\frac{\texttt{Initial area}}{2^{\texttt{number of folds}}}

Initial area = 8.5 x 11 = 93.5 inch²

Here the paper were folded completely in half, length is reduced to half and width reduced to half, that is

Number of folds = 2

\texttt{Area after 2 folds =}\frac{\texttt{Initial area}}{2^{2}}\\\\\texttt{Area after 2 folds =}\frac{93.5}{4}=23.375inch^2

Area after 2 folds = 23.375 inch²

Area of the resulting rectangle = 23.375 inch²

8 0
3 years ago
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