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Amanda [17]
3 years ago
8

Work out the volume of the cuboid 4cm 10cm 15cm

Mathematics
1 answer:
snow_tiger [21]3 years ago
6 0

Answer:

600 m³

Step-by-step explanation:

Attached Below

If it helps, mark as brainliest. : )

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The square root of 343 is 18.520 or 18.52 or also 18
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Question included in the image - geometry problem.
iren [92.7K]

Answer:

y = 116°

Step-by-step explanation:

Given that <em>L₁ </em>|| <em>L</em>₂:

The <u>exterior angle theorem</u> states that the measure of an exterior angle of a triangle is equal to the sum of the two opposite and non-adjacent remote interior angles.  

Also, ∠y° and ∠2x° are <u>same-side interior angles</u> formed by the intersection of the <em>hypotenuse</em> of the triangle that acts as a transversal to the parallel lines, <em>L₁ </em>and <em>L</em>₂.  Given that ∠y° and ∠2x° are <u>same-side interior angles</u>, then it means that they are the supplements of each other, such that the sum of their measures is 180°.  

Now that we have established these definitions, we can proceed with the solution.

<u>Equation 1</u>:  ∠y° + ∠2x° = 180° ⇒ Same-side interior angles

<u>Equation 2</u>:  ∠y° =  ∠x° + ∠84°  ⇒ exterior angle theorem

Substitute the value of m∠y° from Equation 2 into Equation 1 to solve for the value of x:

∠y° + ∠2x° = 180°

∠x° +  ∠84° + 2x° = 180°

Combine like terms:

∠3x° + ∠84° = 180°

Subtract ∠84° from both sides:

∠3x° + ∠84° - ∠84° = 180° -∠84°

∠3x° = 180° - ∠84°

∠3x° = 96°

Divide both sides by 3 to solve for x:

\frac{3x}{3} = \frac{96}{3}

∠x° = 32°

Substitute the value of x into Equation 2 to solve for y:

∠y° =  ∠x° + ∠84°

∠y° =  ∠32° + ∠84°

∠y° =  116°

Verify whether the values for x and y are correct by substituting their values into Equation 1 and 2:

<h3>Equation 1:</h3>

∠y° + ∠2x° = 180°

116° + 2(32)° = 180°

116° + 64° = 180°

180° = 180° (True statement).

<h3>Equation 2:</h3>

∠y° =  ∠x° + ∠84°

116° = 32° + 84°

116°  = 116°  (True statement)

Therefore, the correct answer is: y = 116°.

5 0
3 years ago
What is √80 to thr nearest tenth
nalin [4]

When plugging this into the calculator, you find:

\sqrt{80} \approx \boxed{8.9}


The answer would be 8.9.

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