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lara [203]
3 years ago
5

The figure above shows the solution to a compound inequality. Which inequality does the solution show?

Mathematics
1 answer:
LenaWriter [7]3 years ago
6 0
Ooo i love these ok so the first one is a closed and going left and the other is open and going left aswell therefore
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6m−7)⋅4=left parenthesis, 6, m, minus, 7, right parenthesis, dot, 4, equals ¿Atorado?
mars1129 [50]

Answer:

24m - 28

Step-by-step explanation:

Given the expression (6m−7)⋅4, we are to simplify it. Using the distributive law;

A(B+C) = AB + AC [A is distributed over B and C]

For the expression (6m−7)⋅4, we will distribute 4 over 6m and -7 as shown;

(6m−7)⋅4 = 4(6m) - 4(7)

(6m−7)⋅4 = 24m - 28

Hence (6m−7)⋅4 = 24m - 28

7 0
3 years ago
Anybody help me to solve this question. ​
Mumz [18]

Answer:

\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)} are\ in\ AP

Step-by-step explanation:

Given that (b-c)^2, (c-a)^2 , (a-b)^2 are in AP

To prove: \dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)} are in AP

From given as we know if p , q, r are in AP then 2q= p+r.

2(c-a)^2= (b-c)^2+(a-b)^2\\\\\Rightarrow 2(c^2+a^2-2ac)=b^2+c^2-2bc+a^2+b^2-2ab\\\\\Rightarrow 2c^2+2a^2-4ac= 2b^2+c^2+a^2 -2bc-2ab\\\\\Rightarrow a^2+c^2-2b^2-4ac= -2bc-2ab\\\\\Rightarrow a^2-2b^2+c^2= 4ac-2bc-2ab

Now

\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)}2\dfrac{1}{(c-a)} =\dfrac{1}{(b-c)}+\dfrac{1}{(a-b)}\\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-b+b-c}{(b-c)(a-b)} \\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-c}{(b-c)(a-b)} \\\\\Rightarrow2(b-c)(a-b) = (c-a)(a-c) \\\\\Rightarrow 2(ab-b^2-ac+bc)= -(a-c)^2\\\\\Rightarrow 2ab- 2b^2-2ac+2bc = -a^2-c^2+2ac\\\\\Rightarrow a^2-2b^2+c^2=4ac-2ab-2bc

Which is the result of AP

.

Hence proved

6 0
3 years ago
Which represents the solution of the graphed system of equations, y=x^2-2x and y=-2x-1
elena55 [62]

Answer:

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

Step-by-step explanation:

The solution to the system of equations is at the point where they intercept each other.

y1 = y2

For the given equation;

y=x^2-2x and y=-2x-1

To get the where they intercept, we will equal both equations;

y=x^2-2x = -2x-1

x^2 - 2x = -2x - 1

x^2 - 2x + 2x + 1 =0

x^2 +1 = 0

x^2 = -1

x = √(-1) = i

Since the value of √(-1) is not real.

The system has no real solution.

6 0
4 years ago
The graph shows the weight of a jar when filled with different numbers of marbles.
irakobra [83]

Answer:

B

Step-by-step explanation:

The weight of the jar depends on the number of marbles in it, therefore the weight is the dependent variable (y) and the number of marbles is the independent variable (x). The y-intercept is when x = 0 and since the number of marbles is x, the answer is that the y-intercept represents the weight of the jar without the marbles.

6 0
3 years ago
Use the vertex formula to find the vertex of the quadratic function f(x)=-x^2+6x-10
mixer [17]

Answer:

15

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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