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2 years ago

Use the vertex formula to find the vertex of the quadratic function f(x)=-x^2+6x-10

Mathematics

2 answers:

mixer [17]2 years ago

5 0

Answer:

Step-by-step explanation:

meriva2 years ago

5 0

Answer:

I am sorry I can't help

Step-by-step explanation:

please forgive me

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Which polygon is a pentagon

Mamont248 [21]

Answer: In geometry, a pentagon is a five-sided polygon with five straight sides and five interior angles that sum up to

540

. A pentagon shape is a plane figure, or flat (two-dimensional) 5-sided geometric shape.

Properties of a Pentagon

1. Pentagons have five straight sides

2. Pentagons have five interior angles, which sum to

540

3. The five sides do not intersect

Step-by-step explanation: Hello, I have only told you the properties on how to tell if it's a pentagon, please explain or show some type of image if you still need help!

5 0

2 years ago

30<br> find the length of AB.<br> D 20 C<br> Show your work

vovikov84 [41]

You use Pythagoras theorem for this:
You add 52 and 20 for AC which is 72
So you do
X^2 = 72^2 + 30^2
X^2 =5184 + 900
X^2= 6084
X = 6084 squared root
X= 78

4 0

1 year ago

How do you reduce 6/12

Burka [1]

6/12 is equal to 6 over 12 or .5 or 1/2 when reduced

5 0

2 years ago

Read 2 more answers

Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

7 0

3 years ago

PLEASE HELP!!!

Marizza181 [45]

The function would be f(x)=11,500-.16xPlug in 4 for x

8 0

3 years ago