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3 years ago

The perimeter of a rectangle is 158 cm. If the length is 7 more than 3 times the width:

1 answer:

8 0

Width of rectangle = x
Length =3x+7
Perimeter of rectangle = 158cm
2(l+w)=158
2(3x+7+x)=158
2(4x+7)=158
8x+14=158
8x=158-14
x=144/8
x=18
Therefore the width of the rectangle is 18cm
Length=3x+18+7
54+7=61cm
Area=lxw
=61x18
=1098^2

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The equation is;

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Step-by-step explanation:

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3 years ago

The length of a rectangle is the width minus 8 units. The area of the rectangle is 9 units. What is the length, in units, of the

frez [133]

Length of rectangle is 1 unit

<u>Solution: </u>

Given that

Length of a rectangle is width minus 8 units.

Area of rectangle = 9 square units

Need to calculate the length of rectangle.

Let us assume width of rectangle = x

As Length is width minus 8,

Length of the rectangle = x – 8

$\text{ Area of rectangle }=\text{ width of rectangle }\times \text{ Length of the rectangle }$

$\text{ Area of rectangle }= x\times (x-8)$

$\text { Area of rectangle }=\left(x^{2}-8 x\right)$

As given that area of rectangle = 9 square units

$\begin{array}{l}{\Rightarrow x^{2}-8 x=9} \\\\ {\Rightarrow x^{2}-8 x-9=0}\end{array}$

On solving above quadratic equation for x, we get

$\begin{array}{l}{\Rightarrow x^{2}-9 x+x-9=0} \\\\ {\Rightarrow x(x-9)+1(x-9)=0} \\\\ {\Rightarrow (x-9)(x+1)=0}\end{array}$

When $x-9 =9, x = 9$

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As width cannot be negative, so considering x = 9

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Step-by-step explanation:

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