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Anika [276]
3 years ago
6

How do i find a formula for "1+3+5+7+......+(2n-1)

Mathematics
1 answer:
nata0808 [166]3 years ago
7 0

Answer:

Step-by-step explanation:

common difference d=3-1=2

first term a=1

an=a+(n-1)d

2n-1=1+(l-1)2

2n-1=1+2l-2

2n-1=2l-1

l=n

(i used l for number of terms)

number of terms=n

S_{n}=\frac{n}{2} (first ~term+last~term)\\=\frac{n}{2} (1+2n-1)\\=n^2

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If the lcm of two numbers a and b is 40 what is the lcm of 7 a^2 and 7b^2
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Answer:

11,200

Step-by-step explanation:

Given that the lcm of a and b  is 40 then a and b are factors of 40. All the multiples of 40 as sets are 1 and 40, 2 and 20, 4 and 10, 5 and 8. Of all these, only 5 and 8 would give a lcm of 40.

Let a = 5 and b = 8 as such,

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3 years ago
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